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3 years ago

10

What is the volume of a cone that has a height of 10 feet and a base with a diameter of 2 and half feet?

1 answer:

lyudmila [28]3 years ago

6 0

Volume of a cone: 1/3 $\pi$ r²h
r is the radius (diameter ÷ 2) and h is the height.

Find the radius first using the diameter: 2 $\frac{1} {2}$ ÷ 2 = 1.25

Now plug in the numbers into the formula.

1/3 $\pi$ 1.25²10 = <span>16.4
</span>
The volume of the cone is 16.4 cubic feet.

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Circle D is shown with the measure of the minor arcs which segment are congruent

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3 years ago

What is the solution to this equation?

Morgarella [4.7K]

Answer:

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3 years ago

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

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Thus

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Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago

Which coordinate lies in the solution set for

tatyana61 [14]

Answer:

Step-by-step explanation:

to do this, u would just sub ur answer choices into the inequalities and see what is true. Keeping in mind, that ur point has to satisfy both inequalities for it to be a solution.

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2(3) + 3 < 12 3(3) - 2(3) > 2

6 + 3 < 12 9 - 6 > 2

9 < 12....true 3 > 2....true

(3,3) lies in the solution set <==

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3 years ago

Pls help because I’m not sure

leva [86]

B

Step-by-step explanation:

8 0

2 years ago