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3 years ago

(2x1)+(2x4)=2x(?+?) what’s the ?

Mathematics

1 answer:

valina [46]3 years ago

4 0

Answer:

Step-by-step explanation:

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Hey yall i would really appreciate your help on this plz

Katarina [22]

Answer:

the length of the opposite side (x), is 27.2

Step-by-step explanation:

For the given right triangle problem;

the opposite side of the given angle, opp. = 22

the hypothenuse side, hypo. = x

given angle of the triangle, θ = 54⁰

The length of the opposite side (x), is calculated as follows;

$sin \ \theta = \frac{opp.}{hypo.} \\\\sin (54) = \frac{22}{x} \\\\x = \frac{22}{sin(54)} \\\\x = 27.2$

Therefore, the length of the opposite side (x), is 27.2

6 0

3 years ago

Which products have the same sign as (Negative 2 and StartFraction 3 over 7 EndFraction) (Negative StartFraction 6 over 11 EndFr

avanturin [10]

Answer : A

Hope this helps

5 0

3 years ago

On Reese’s most recent phone bill bill, 80% of the minutes she used were calling her mother. If she talked to her mother for 348

dexar [7]

She used 278.4 minutes

5 0

3 years ago

Find the smallest positive $n$ such that \begin{align*} n &\equiv 3 \pmod{4}, \\ n &\equiv 2 \pmod{5}, \\ n &\equiv

Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number $x$ such that taking it mod 4, 5, and 7 leaves the desired remainders:

$x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6$

Taken mod 4, the last two terms vanish and we have

$x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4$

so we multiply the first term by 3.

Taken mod 5, the first and last terms vanish and we have

$x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5$

so we multiply the second term by 2.

Taken mod 7, the first two terms vanish and we have

$x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7$

so we multiply the last term by 7.

Now,

$x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147$

By the CRT, the system of congruences has a general solution

$n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}$

or all integers $27+140k$ , $k\in\mathbb Z$ , the least (and positive) of which is 27.

3 0

3 years ago

-15.6 = -3.9r<br> please include an explanation of how you got your answer :) thanks

Mumz [18]

Here is the equation:

$-15.6 = -3.9r$

Since both decimals are negative, the answer will be positive.

Negative times Negative = Positive

Divide both sides by -3.9 to leave the variable alone:

$-15.6 \div -3.9 = -3.9r \div -3.9 \\ 4 = r$

r is equal to 4 → r = 4

5 0

2 years ago