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2 years ago

5 times 4 times 2 times 2 divided by 2 minus 4

Mathematics

1 answer:

Elenna [48]2 years ago

6 0

Answer:

Step-by-step explanation:

5 x 4 = 20

20 x 2 = 40

40 x 2 = 80

80 ÷ 2 = 40

40 - 4 = 36

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-5x-12>6x-4 Solve the inequality and give the answer in interval notation.

lora16 [44]

-5x-12>6x-4

To Solve the inequality we need to get x alone

-5x-12>6x-4

first we remove -12, for that we add 12 on both sides

-5x-12+12>6x-4+12

-5x > 6x +8

Now subtract 6x from both sides

-5x -6x> 6x-6x +8

-11x > 8

Divide by -11. when we divide by -11 we flip the inequality . so > becomes <

$x < -\frac{8}{11}$

We need to give the answer in interval notation.

x is less than -8/11 so x value starts from -8/1 and goes to -infinity(left)

So interval notation is (-∞, $-\frac{8}{11}$ )

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2 years ago

0.729 rounded by the nearest tenth

katrin [286]

0.7 is rounded to the tenth place

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2 years ago

Read 2 more answers

Aubrey finished 2/9 of a project on Monday and 1/4 of the project of Tuesday. How much of the project has Aubrey completed?

riadik2000 [5.3K]

Answer:

17/36

Step-by-step explanation:

We have to find a common denominator, so the first common denominator for 4 and 9 is 36. 9x4=36, so we multiply 2 by 4, which equals 8. 4x9-36, so we multiply the 1 by 9, and get 9. Then we add the numerators, 8 and 9, and get 17. So it's 17/36

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2 years ago

Write one digit on each side of 23 to make a four digit multiple of 72. How many different solutions does this problem have?

user100 [1]

Answer:

This problem has two possible solutions.

2232

7236

Step-by-step explanation:

To be divisible by 72, a number has:

To be divisible by both 8 and 9 at the same time.

It is divisible by 8 if it's last two digits are divisible by 4.

It is divisible by 9 it the sum of it's digits is a number divisible by 9.

a23b

3b must be divisible by 4. In the thirties, the numbers that are divisible by 4 are 32 and 36. So b = 2 or b = 6.

a232

2 + 3 + 2 = 7

The higest possible value of a is 9 and the lowest is 1.

Between 8 and 16, only 9 is divisible by 9. So a = 2.

a = 2, b = 2 is one of the solutions.

a236

2 + 3 + 6 = 11

The higest possible value of a is 9 and the lowest is 1.

Between 12 and 20, only 18 is divisible by 9. So we need a = 7

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3 years ago

If 2a + 7b+2c=16 and 2a + 3b +2c= 8, then b = ?<br> (A)-2<br> (B) O<br> (C) 2<br> (D) 4<br> (E) 6

Sauron [17]

Answer:

Step-by-step explanation:

Given equations 2a + 7b+2c=16 and 2a + 3b +2c= 8, you want to know the value of b.

<h3>Solution</h3>

The coefficients of 'a' and 'c' are the same in the two equations, so we can eliminate those variables by subtracting one equation from the other. We can keep the resulting coefficient of 'b' positive if we subtract the second equation from the first.

(2a +7b +2c) -(2a +3b +2c) = (16) -(8)

4b = 8 . . . . . . . simplify

b = 2 . . . . . . . divide by 4

5 0

1 year ago

5 times 4 times 2 times 2 divided by 2 minus 4​

5 times 4 times 2 times 2 divided by 2 minus 4