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Stells [14]
3 years ago
6

How to expend 5(3z+b) +4(b-2z) using distributive property​

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

5 (3z+b) +4 (b-2z)

5(3) (z+b) +4(2) (b-z)

5x3= 15 / 4x2= 8 -- Input (below)

Answer= 15 (z+b) +8 (b-z)

Step-by-step explanation:

VMariaS [17]3 years ago
5 0

Answer:

7z+9b

Step-by-step explanation:

distrbuite the 5:

15z+5b + 4(b-2z)

then distrubite the 4:

15z + 5b + 4b - 8z

collect like terms:

7z+ 9b

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Emerson has an associate degree. Based on the bar chart below, how will his employment opportunities change from 2008-2018?
ANEK [815]

Answer:

19% change

Step-by-step explanation:

Since, Emerson has an associate degree,

His employment is 19% changed in 10 years, i.e. from 2008 to 2018.

Because the bar graph shown the percentage of change in employment from 2008 to 2018.

Also, Employment of associate degree is most affected in 10 years.

And those who have job training and work experience is least affected in these 10 years.

5 0
3 years ago
anthony bought an 8 foot board.He cut off 3/4 of the board to build a shelf,and gave 1/3 of the rest to his brother for an art p
e-lub [12.9K]
Convert your feet to inches.
So 8 times by 12 = 96 inches
if you have 3/4 of the board used. 
3/4= .75 
if you were to times 96 by .75 = 72 inches.
So you used 72 inches and you have 24 inches left

now do 1/3= .33
times .33 by 24= 8
8 inches is how long you would give to Anthony's brother.
7 0
3 years ago
Read 2 more answers
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

|PQ×PS| = √9600

|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
3 years ago
I need help..... please
Bogdan [553]

Answer:

Step-by-step explanation:

I would say Town residents

5 0
2 years ago
What number must you add to complete the square?<br> x^2 + 2x = -1
Andru [333]
\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

6 0
3 years ago
Read 2 more answers
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