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Irina18 [472]
3 years ago
11

a rectangular field has a length that is two meters more than the breadth,if the total area of the field is 168m², calculate the

dimensions of the field​
Mathematics
1 answer:
sdas [7]3 years ago
6 0

Answer:765

Step-by-step explanation:

Jjjjjjh kingdom

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D

Step-by-step explanation:

If we look at the right side of the equation we see that the y-intercept is 2, so we will place a point on (0,2).

Next, we look to see if the slope of the graph if positive or negetive, and to see what is the slope (2x).

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*Note the following:

if < then the line is dotted and the shading will be under the line.

if > then the line is dotted and the shading will be above the line.

if <_ then the line is solid and the shading will be under the line.

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It is a lot of information if you look at it, but with practice it can be made easier.

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3 years ago
The garden club earned $15, 15 per hour by weeding neighborhood gardens for t hours. A generous donor has agreed to double their
natima [27]

Answer:

The answer should be $30.

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3 years ago
Express (5r+2)(5r-2) in standard polynomial form
Alex_Xolod [135]
25r^2-4 rewriten in standard polynomial form

8 0
4 years ago
Help!!!!!!!!!!!!
labwork [276]

Answer:

None of the Above

Step-by-step explanation:

As it is given that

cosФ= 3/2

and Ф lies in quadrant 4

Now in quadrant 4 we know that by the rules of trigonometry that

cos Ф is positive in 4th quadrant also in 4th quadrant

and sinФ is negative in 4th quadrant

also we know that by simple rules of trigonometry in a right angled triangle

cos Ф=\frac{Base}{Hypotenuse} =\frac{3}{2}

now from the law of trigonometry

cos²Ф+sin²Ф=1

From this we derive the value of sinФ

solving the equation

sin²Ф=1-cos²Ф

Putting in the values of cos Ф

sin²Ф=1-(\frac{3}{2})^{2}

sin²Ф=1-(\frac{9}{4})

solving the fraction

sin²Ф=(\frac{4-9}{4})

sin²Ф=(\frac{-5}{4})

so taking square root of both sides

\sqrt{sin^{2}\alpha}=\sqrt{\frac{-5}{4} }

here

\alpha=Ф

so it becomes

sin Ф=\frac{\sqrt{-5} }{2}

as we know that in imaginary numbers

\sqrt{-1} = ι

so the given becomes

sin Ф=\frac{{-5ι} }{2}

Which is the value of sin Ф

And in the given values we can see that it is none of the values

Also seeing the question we can see that the question is absurd because

cos Ф= base / hypotenuse

in our question we can see that base =3 and hypotenuse = 2

but in real geometry this is the rule that hypotenuse can never be smaller then base either it is equal to base or greater then base

the formula for finding value of finding hypotenuse is

hypotenuse ² = base ² + perp ²

so this formula shows that if perp is 0 then hypotenuse will be equal to base

in other cases it would be greater then base





5 0
3 years ago
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