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2 years ago

PLEASE HELP ASAP!!

Mathematics

1 answer:

Alex Ar [27]2 years ago

7 0

Answer:

Step-by-step explanation:

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Four students simplify the expression below: 6 + 4 x 10 ÷ 2 Anshu's solution is 25 , David's solution is 46 , Jimmy's solution i

Mrac [35]

Answer:

Jimmy; 26

Step-by-step explanation:

PEMDAS

Parentheses Exponents Multiplication Division Addition Subtraction

6 + 4 * 10 / 2 = 6 + 40 / 2

6 + 40 / 2 = 6 + 20

6 + 20 = 26

7 0

2 years ago

Whats the volume of the cylinder? Round your answer to the nearest hundred the top is B the left side of the cylinder is 13cm th

Wittaler [7]

Answer:

The volume of the cylinder is 163.3 m³.

Step-by-step explanation:

Given that,

Height = 13 cm

Base = 4 cm

So, radius = 2 cm

We need to calculate the volume of the cylinder

Using formula of cylinder

$V=\pi r^2h$

Where, r = radius

h = height

Put the value into the formula

$V=\pi\times(2)^2\times13$

$V=163.3\ cm^3$

Hence, The volume of the cylinder is 163.3 cm³.

6 0

2 years ago

ULT ma<br> 4. Write an expression, then evaluate.<br> a. 1/4of the sum of 18 and 6

OlgaM077 [116]

Answer: Required expression: $\dfrac14\times(18+16)$

Result: $\dfrac{17}{2}$

Step-by-step explanation:

Given phrase: $" \dfrac14\text{ of the sum of } 18\text{ and }6. "$

Required expression: $\dfrac14\times(18+16)$ ['+' used to express sum, 'x' used in place of 'of']

Since 18+16 = 34

Then,

$\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}$

Hence, $\dfrac14\times(18+16)=\dfrac{17}{2}.$

8 0

2 years ago

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$