Answer:
A)
y^2-6y = 0
or, y(y-6) = 0
or, y = 0 or y = 6
B)
n^2+5n+7 = 7
or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)
or, n^2+5n = 0
or, n(n+5) = 0
or, n=0 or n= -5
C)
2t^2-14t+3 = 3
or, 2t^2-14t = 0
or, 2t(t-7) = 0
or, t=0 or t=7
D)
1/3x^2+3x-4 = -4
or, 1/3x^2+3x = 0
or, 1/3x(x+9) = 0
or, x=0 or x= -9
E)
Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.
THANK YOU FOR READING.
For number 5, you just plug -2 into x. We now have g(-2)=3(-2)+1. This gives us g(-2)=-5.
This is the same for 6. h(-6)=-3(-6)-2. This gives us h(-6)=16.
The answer is g(-2)=-5. The other answer is h(-6)=16.
Answer:
81
Step-by-step explanation:
18*9=162
162*
=81
7 . 112
8 . 246
for number 7 , you multiply 8 by 16 to get 128 then subtract both windows so you get 112
for number 8 , you find the area of the rectangle which is 10x26 = 260 then add the triangles area which is 130 and you get 390 then subtract the 16 window and 128 door
