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3 years ago

1. Based on the construction below, which conclusion

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

Answer: B ,I just completed the assignment

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Can't figure it out!!

Zanzabum

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x} \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\
$

$\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}$

8 0

3 years ago

In the following diagram, line m is parallel to line n and line q intersects the parallel lines at

joja [24]

Answer:

108°

Step-by-step explanation:

We know for a theorem that A = B, so:

4x + 28 = 2x + 68

Isolating the x:

2x = 40

x = 20

Now let's plug in the equation for A:

4(20) + 28 = 108°

8 0

2 years ago

The Sugar Sweet Company is going to transport its sugar to market. It will cost $7500 to rent trucks, and it will cost an additi

Inga [223]

Let C represent the total cost (in dollars),
and let S represent the amount of sugar (in tons) transported

equation:
C(s) = 225s + 7500

find the total cost to transport 11 tons of sugar.
C(11) = 225(11) + 7500
C(11) = 2475 + 7500
C(11) = 9975

hope it helps

7 0

3 years ago

PLEASE HELP!!!! will give brainliest to whoever answers

kumpel [21]

Answer:

Step-by-step explanation:

the answer is 45 sin

3 0

2 years ago

Find the quotient 3^15/3^3

Sati [7]

There is a property called "Quotient of powers property", which states that:

$\frac{a^m}{a^n}=a^{(m-n)}$

Where "a" is the common base and "m" and "n" are exponents.

For this case, you have:

$\frac{3^{(15)}}{3^3}$

Then, in order to find the quotient, you must apply the Quotient of powers property. You need to write the common base (in this case is 3) and then subtract the exponents.

So, you get that the quotient is:

$\frac{3^{(15)}}{3^3}=3^{(15-3)}=3^{(12)}$

6 0

1 year ago