Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Answer:
1.27, -6.27 to the nearest hundredth,
or if you require it in exact form,
-2.5 + √14.25, -2.5 - √14.25.
Step-by-step explanation:
x^2 = -5x + 8
x^2 + 5x = 8
Competing the square:
(x + 2.5)^2 - 6.25 = 8
(x + 2.5) = 14.25
x + 2.5 = +/-√14.25
x = -2.5 + √14.25, -2.5 - √14.25
x = -2.5 + 3.77, -2.5 - 3.77
= 1.27, -6.27.
Answer:
x=13.5
Step-by-step explanation:
Using the formula:
Sin theta=opposite/hypotenuse
Where theta=57 degrees
opposite =10.8
hypotenuse =x
Sin57=10.8/x
Xsin57=10.8
x=10.8/sin57
x=10.8/0.8
x=13.5
6,720,000. I hope that helps!
Answer:
1,2,3
Step-by-step explanation:
you can't have half of a dog so it is all the whole numbers
