Answer:
Choice A: x^2−2x+4− 15/x+2
Step-by-step explanation:
Answer:
1+6y= "7y=7"
1+5y= "6y=4"
Step-by-step explanation:
X represents "1" so you replace your "X" with "1" and solve the equation.
Answer:
Step-by-step explanation:
Sec B
1) 5p⁻³ = 8*5⁻²
p⁻³ = 2³*5⁻²/5
p⁻³ =2³*5⁻³ { 1/a^m = a^-m}
p⁻³ = 5⁻³ /2⁻³ {a^m = 1/a^-m}
p⁻³ = (5/2)⁻³
p= 5/2
2) 4x² = 81
x² = 81/4
x² = 9² /2²
x² =(9/2)²
x = 9/2
3) 9^x/3 =81
9^x/3 = 9^2
Comparing the powers, x/3 = 2
x = 2*3 =6
x = 6
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ = ≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM = ≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
Answer:
1. 3sqrt(2)
Choice C
2. 2sqrt(3)
Choice D
Step-by-step explanation:
1. sqrt(x+3)
sqrt(15+3)
sqrt(18)
sqrt(9*2)
sqrt(9)sqrt(2)
3sqrt(2)
Choice C
2. 6/sqrt(x)
6/sqrt(3)
no radicals in the denominator, multiply by 1 in the form of the radical
6/sqrt(3) * sqrt(3)/sqrt(3)
6sqrt(3)/ (sqrt(3)*sqrt(3))
6sqrt(3)/3
2sqrt(3)
Choice D