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3 years ago

7

I need help ASAP Please and thanks

2 answers:

pishuonlain [190]3 years ago

8 0

It’s the 3rd one hope this helps

Leokris [45]3 years ago

3 0

Answer:its number 3

Step-by-step explanation:

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Write the equation in Standard Form.<br> y+1 = - 4 (x+4)

hichkok12 [17]

Y+4x+7 is the answer

8 0

3 years ago

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Is the enlargement or a reduction? Find the scale factor of the dilation.<br> Explain

malfutka [58]

Good evening ,

Answer:

In this case the dilation is a reduction (as you can see the image triangle is smaller than the original triangle)

and also the scale factor = OA’/OA = 2/6 = 1/3

since -1 < 1/3 < 1 then it’s a reduction.

Step-by-step explanation:

Look at the photo below for more details (notice OA’ and OA).

________________________________________________

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4 0

3 years ago

1/2 of 3 + 3/4 of 3 +1/2 of 2=

Vedmedyk [2.9K]

=3/2+ 9/4+ 2/2
=1.5+ 2.25+ 1
=4.75

6 0

3 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

2 years ago

Math help questions <br>

Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of $\$800 \times 1.07^t$ .

We want the find the number of years n such that

$\$856 \times 1.07^n = \$1400$

Solve for n :

$856 \times 1.07 ^n = 1400$

$1.07^n = \dfrac74$

$\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)$

$n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)$

$n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}$

4 0

1 year ago

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