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kirill115 [55]
3 years ago
8

HELPPP PLSSSS ITS ALGEBRA

Mathematics
1 answer:
kaheart [24]3 years ago
3 0

Answer:

whats the question?

Step-by-step explanation:

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Graphing standard form inequalities help plz
Art [367]

Answer:

The axis of symmetry

The x-value of the vertex

5 0
2 years ago
If the square root of 16 = x, then x2 =
solmaris [256]

Answer:

8

Step-by-step explanation:

16=x

16 square root is 4

16=4

x2

(4)2= 8

6 0
3 years ago
Read 2 more answers
A binary operation is defined on the set of real numbers ℝ by
zloy xaker [14]

Answer:

I. m = 2401

II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

Step-by-step explanation:

I. Determination of m

x ∆ y = x² − 2xy + y²

2 ∆ − 5 = √m

2² − 2(2 × –5) + (–5)² = √m

4 – 2(–10) + 25 = √m

4 + 20 + 25 = √m

49 = √m

Take the square of both side

49² = m

2401 = m

m = 2401

II. Simplify ((n+1) ∆ y)/n

We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:

x ∆ y = x² − 2xy + y²

(n+1) ∆ y = (n+1)² – 2(n+1)y + y²

(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²

(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1

(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1

(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1

(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1

(n+1) ∆ y = (n – y + 2)(n – y) + 1

((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n

((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

7 0
3 years ago
An organization has members who possess IQs in the top 4% of the population. If IQs are normally distributed, with a mean of 100
murzikaleks [220]

Answer:

The minimum IQ score will be "126".

Step-by-step explanation:

The given values are:

Mean

\mu = 100

Standard deviation

\sigma=15

Now,

⇒ P(z>x)=4 \ percent \ i.e., 0.04

⇒ P(z>\frac{x- \mu}{\sigma} )=0.04

⇒ 1-P(z \leq \frac{x-100}{15})=0.04

⇒ \frac{x-100}{15}=z0.96

            =NORMDIS(z=0.96)

            =1.751

⇒ x=100+15\times 1.751

      =126.265 \ i.e., 126

7 0
3 years ago
Why is 4 laps in 10 minutes and 6 laps in 15 minutes proportional
Shtirlitz [24]
If you break it down it goes to 2 laps every 5 minutes. So any set that follows this "pattern" would be proportional
3 0
3 years ago
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