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Delvig [45]
3 years ago
15

At the movie theatre, child admission is $6.40 and adult admission is $9.90. On Friday, 154 tickets were sold for a total sales

of $1230.60. How many adult tickets were sold that day?
Mathematics
1 answer:
Minchanka [31]3 years ago
4 0
6.40x+9.90(154-x)=1230.90
Solve for x
X=84 for child

154-84=70 for adults
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0.41

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A hot air balloon is flying above Groveburg. To the left side of the balloon, the balloonist measure the angle of depression to
const2013 [10]

Answer:

The answer is 1.4 miles ⇒ answer (d)

Step-by-step explanation:

* Let the balloon is at the vertex A, and the soccer fields

  at vertex B and the football field at vertex C

∴ m∠B = 20° 15' = 20.25°

∴ m∠C = 62° 30' = 62.5°

∴ m∠A = 180 - 20.25 - 62.5 = 97.25°

∵ BC = 4 miles

* By using the sin Rule:

∵ AC/sin(B) = BC/sin(A)

∴ AC = (BC)(sinB)/sin(A)

∴ AC = [4 × sin(20.25)] ÷ sin(97.25) = 1.395 ≅ 1.4 miles

∴ The distance from the balloon to the football filed = 1.4 miles

4 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST<br><br> if y=12 when x=6/7, find x when y=16
il63 [147K]

Answer:

y = 12  when x = 6/7.

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Step-by-step explanation:

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Find the missing angle.<br> 65<br> 50<br> 60<br> 35
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Step-by-step explanation:

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If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

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\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

\log_db=\dfrac1{-\frac34\cdot2}=-\dfrac23

Similarly,

\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

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So we end up with

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###

Another way to do this:

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Then

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So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

4 0
2 years ago
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