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3 years ago

$1000 invested with compound interest at a rate of 15% per year for 9 years.

Mathematics

1 answer:

ivolga24 [154]3 years ago

5 0

Answer:

The Final Investment Value is $\$3,517.88$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=9\ years\\ P=\$1,000\\ r=0.15\\n=1$

substitute in the formula above

$A=1,000(1+\frac{0.15}{1})^{1*9}$

$A=\$3,517.88$

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