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2 years ago

7

If f(x)=2x^4-x^3-3x^2+14 then f'(3)=

1 answer:

Anna71 [15]2 years ago

4 0

Answer:

f(3)=122

Step-by-step explanation:

You might be interested in

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

2 years ago

How many complex roots does the polynomial equation below have?

erastova [34]

Answer:

4.

Step-by-step explanation:

I will have one real root = fifth root of 3.

As it has a total of 5 roots ( By the Fundamental Theorem of Algebra) then it must have 4 complex roots.

5 0

2 years ago

Simplify the expression 8^2 +9 (12/3x2)- 7

Zarrin [17]

1)12 ÷ 3 = 4.
2) 4×2= 8.
3) 9× 8= 72.
4) 8² = 64
5) 64+ 72 = 136
6) 136 - 7 = 129.

If you just want to simplify the expression you get: 8² + 9(8) - 7
But when you simplify that you get the answer below.
ANSWER: 129

6 0

3 years ago

At one gas station, gas costs $2.75 per gallon. Complete the equation that relates the total cost, C, to the number of gallons o

dolphi86 [110]

Answer:

C = 2.75

Step-by-step explanation:

it does not tell how much there for it is 1 gallon

6 0

2 years ago

the length of your garden must exceed the width of the garden by 3 feet. you only have 58 feet of fencing to go around the perim

DedPeter [7]

First let us represent
x-width
x+3-length

Since it has a width and length, we can say it is a rectangle so the formula for the perimeter of it is 2(l+w)

p=2(l+w)
58=2(x+3+x)
58=(2x+3)2
58=4x+6
52=4x
x=13

the width is 13 and the length is 16

7 0

2 years ago