We'll use standard labeling of right triangle ABC, C=90 degrees, legs a, b, hypotenuse c.
11.
Right triangle, cliff peak A, boat B, angle opposite cliff is B=28.9 deg. adjacent leg a=65.7 m, cliff height is leg b.
tan B = b/a
b = a tan B = 65.7 tan 28.9° = 36.3 m
12.
Similar story, boat at B, opposite b=3.5 m, rope c=12 m
sin B = b/c
B = arcsin b/c = arcsin (3.5/12) = 17.0°
13.
c=124 m, A=58°
sin A = a/c
a = c sin A = 124 sin 58 = 105.2 m
14.
That's a hypotenuse c=4-1.2 = 2.8 m to a height b=1.8m so
cos A = b/c
A = arccos b/c = arccos (1.8/2.8) = 50.0°
15.
Not a right triangle, an isosceles triangle. Half of it is a right triangle with hypotenuse one arm, c=9.8 cm and angle opposite half the base of B=62/2=31°. We're after d=2b:
sin B = b/c
b = c sin B
d = 2b = 2 c sin B = 2(9.8) sin 31 = 10.1 cm
Almost equilateral
Unusual notation. I won't fuss with it.
a. We have isosceles PRT, so angle RPT = angle RTP.
By the definition of angle bisector, angle MTP = angle MTF, and angle MPT = angle MPU.
We have m angle RTP = m angle MTF + m angle MTP = 2 m angle MTP
Similarly, m angle RPT = 2 m angle MPT
2 m angle MTP = 2 m angle MPT
angle MPT = angle MPT
That's the first part.
b. That makes MPT isosceles.
c. 2x+124=180
2x = 56
x = 28 degrees
MTP = 28 degrees
d. We have angle RPT=angle RTP=56 so PRT=180-2(56)=68 degrees
PUT = 180 - UTP - UPT = 180 - 28 - 56 = 96 degrees
Bad drawing, PUT looks acute.
angle PRT = 68 degrees, angle PUT = 96 degrees
Answer: commom resources good
Step-by-step explanation:
The question above signifies that I can't eliminate shoes from my list. To me, shoes are inexcludable. You can see that as my income increases, my purchases of shoes increase.
I chose common resources good because they are non-excludable (something difficult to eliminate), but can compete with other goods. This means that their availability to other people decreases when they are being used up.
Other types of goods besides common resources good are
- Private goods (products that are easily eliminated and rival)
-Club goods (excludable products but non rival)
-Public goods (unable to eliminate and non-rival)
(f∘g)(x) is equivalent to f(g(x)). We solve this problem just as we solve f(x). But since it asks us to find out f(g(x)), in f(x), each time we encounter x, we replace it with g(x).
In the above problem, f(x)=x+3.
Therefore, f(g(x))=g(x)+3.
⇒(f∘g)(x)=2x−7+3
⇒(f∘g)(x)=2x−4
Basically, write the g(x) equation where you see the x in the f(x) equation.
f∘g(x)=(g(x))+3 Replace g(x) with the equation
f∘g(x)=(2x−7)+3
f∘g(x)=2x−7+3 we just took away the parentheses
f∘g(x)=2x−4 Because the −7+3=4
This is it
g∘f(x) would be the other way around
g∘f(x)=2(x+3)−7
now you have to multiply what is inside parentheses by 2 because thats whats directly in front of them.
g∘f(x)=2x+6−7
Next, +6−7=−1
g∘f(x)=2x−1
Its a lts easier than you think!
Hope this helped
