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Tresset [83]
3 years ago
6

What can be concluded from the graph shown here

Mathematics
1 answer:
lubasha [3.4K]3 years ago
5 0

Answer:

There was no graph attached here, if you can attach the graph then I can help out.

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Solve the following equation and show all of your steps: x^2+x−1=0
DaniilM [7]
Quadratic formula since this trinomial is not factorable.
\frac{ - b +  -  \sqrt{ {b}^{2} - 4ac } }{2a}  \\  \frac{ - 1 +  -  \sqrt{ {(1)}^{2} - 4(1)( - 1) } }{2(1)}  \\  \frac{ - 1 +  -  \sqrt{1 + 5} }{2}  \\  \frac{ - 1 +  -  \sqrt{6} }{2}  \\ x =   \frac{ - 1 +  \sqrt{6} }{2}  \\ x =   \frac{ - 1 -  \sqrt{6} }{2}
5 0
3 years ago
Write a quadratic function f whose zeros are - 5 and 7.
weeeeeb [17]
Our two binomials are (X-5)(X-7)

If we FOIL those two terms [x*x = x2; x*-7 = -7x; x*-5 = -5x; -5*-7 = 35] and combine the like terms, we're left with one of many quadratic function
Answer
x2-12x+35
3 0
3 years ago
The number line shows four points. Which point represents the approximate location of 83?
makkiz [27]
Answer: point A


Hope this helped have a nice day
8 0
2 years ago
Convert 0.595 into percent​
Nadusha1986 [10]

Answer:

Hi there!

Your answer is:

59.5%

Step-by-step explanation:

To chance a demical into a percent, multiply by 100!

.595 × 100 = 59.5%

I hope this helps!

4 0
3 years ago
Read 2 more answers
how is building a triangle with different side lengths given different than building a quadrilateral with given side lengths?​
Mariana [72]

Answer:

there can only be one possibility for a triangle when given the lengths of all the sides but for a quadrilateral the measure of the angles could differ depending on the person building the,. this is because triangles are more stable than quadrilaterals meaning that their side lengths follow a lot more rules than quadrilaterals do, for example the length of the side lengths can indicate whether or not that triangle is an acute, obtuse, or right triangle, and this is also evident by considering that you can use the SSS theorem to indicate two triangles are congruent, but for quadrilaterals you cant do that

Step-by-step explanation:

8 0
3 years ago
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