Suppose two dice are tossed and the numbers on the upper faces are observed. let s denote the set of all possible pairs that can
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11. 8 * 18 = 144 in³, Option D
12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 = 240 cm³, Option D
13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 = 288pi or ≈ 904.78, Option C
14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 = 12 in³, Option B
15.
>> 16x = 180 >> x = 11.25 so Option B
16. Option D, 10 cm.
17. Option C, 8.5 in
18. Option B. 10.2 km
19. Option D. 0.82
20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) = 9.96 m, Option C.
12. Half the height of 8 cm is 4 cm. Volume = 4 * 6 * 10 = 240 cm³, Option D
13. Double the dimensions you get 8 cm for the height, 6 cm for the radius. Then plug in. V = pi * (6)² * 8 >> pi * 36 * 8 = 288pi or ≈ 904.78, Option C
14. Half of all the dimensions are 1 in, 4 in, and 3 in. 1 * 4 * 3 = 12 in³, Option B
15.
16. Option D, 10 cm.
17. Option C, 8.5 in
18. Option B. 10.2 km
19. Option D. 0.82
20. cos 30 = b / 11.5 >> b = 11.5(cos (30)) = 9.96 m, Option C.