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cricket20 [7]
2 years ago
6

Suppose two dice are tossed and the numbers on the upper faces are observed. let s denote the set of all possible pairs that can

be observed. [these pairs can be listed, for example, by letting (2, 3) denote that a 2 was observed on the first die and a 3 on the second.]
Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
5 0

Suppose two dice are tossed and the numbers on the upper faces are observed. let s denote the set of all possible pairs that can be observed.

Answer: If two dice are tossed, there are 6^{2} =36 possible outcomes.The possible pairs that can be observed are given in a set denoted by s below:

\left[\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}\right]

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Answer:  
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1)   " 30, 60, 50 " .

2)  " 30, 50, 6 " .

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<u>Note</u>:
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1)  30 * 60 * 5 = 9,000 .

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8 0
3 years ago
Read 2 more answers
A food store makes a 12-lb mixture of granola, clusters, and raisins. The cost of granola is $1.00 per pound, clusters cost $3.0
Semenov [28]

Answer:

The food store used  3 lbs of clusters, 6 lbs of granola, and 3 lbs of raisins.

Step-by-step explanation:

Given that:

A food store makes a 12-lb mixture of granola, clusters, and raisins.

The cost of granola = 1.00 per pound

The cost of clusters = 3.00 per pound

The cost of raisins = 2.00 per pound

Let granola be = g; cluster be c and raisins be r

Then, g + c + r = 12

Similarly, the mixture calls for twice as much granola as clusters.

2c + c + r = 12

3c + r = 12

r = 12 - 3c

2c(1) + 3c + 2r = 21

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24 - c  = 21

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Thus, cluster c = 3 lbs

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raisins = 12 - 3c

= 12 - 3(3)

= 12 - 9

raisins = 3 lbs

4 0
3 years ago
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