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Maksim231197 [3]
3 years ago
5

Answer the question above.

Mathematics
1 answer:
Likurg_2 [28]3 years ago
3 0

Answer:

576.09

Step-by-step explanation:

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What did I do wrong in notes, and why is the answer what it shows on screenshot
Svet_ta [14]

Answer:

Hope you find it helpful and usef

7 0
3 years ago
What single decimal multiplier would you use to increase by 18% followed by a<br> 12% decrease?
ValentinkaMS [17]

Answer:

The single decimal multiplier used to increase by 18% followed by a  12% decrease is 0.21.

Step-by-step explanation:

Let 'x' be the number

As first the number has to be increased by 18%

so

Step 1: write the percentage '18%' in decimal form

18% = 0.18    

Step 2: For percentage increases: add the decimal to 1

1 + 0.18 = 1.18    

Step 3: Multiply the number x by the multiplier, found in Step 2

x × 1.18 = 1.18x

<u><em>NEXT WE HAVE TO DECREASE 1.18x by 12%</em></u>

Apply the same method but with a number 1.18x

  • Write the percentage '12%' in decimal form

12% = 0.12

  • For percentage decreases: subtract the decimal to 1

1 - 0.18 = 0.18

  • Multiply the number 1.18x by the multiplier, found in Previous step

1.18x × 0.18 = 0.21x

Therefore, the single decimal multiplier used to increase by 18% followed by a  12% decrease is 0.21.

7 0
3 years ago
parking garage has 5 floors. If 117 cars can be parked on each floor, how many total cars can park in the garage? Drag numbers t
mr Goodwill [35]

Answer:

585 cars

Step-by-step explanation:

Given

Floors = 5

Cars = 117 per floor

Required

Determine the total number of cars

This is calculated by multiplying number of cars per floor by number of floors.

Total = Floors*Cars

Total = 5  * 117

Total = 585

<em>Hence, there are 585 cars in total</em>

6 0
3 years ago
Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac
agasfer [191]

Answer:

a) \frac{8}{9} =0.89

b) 0.8413

Step-by-step explanation:

we know that

P(║ x -\mu║ \leq  k\sigma) \geq 1 -\frac{1}{k^2}

so, \mu = 150, \sigma = 20

k =  \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3

P(║ x -150 ║ \leq  3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}

x - N(150, 20^2)

P(X \leq 170) = 0.8413447

check

P norm = \frac{170 - 150}{20}= 0.8413447

8 0
3 years ago
15. What is the width of each bin? (1 point)
Pavel [41]
15) Answer is B because you can clearly see it's only 1 inch
5 0
3 years ago
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