X^2 - 49 = (x + 7)(x - 7) = x^2 - 7x + 7x = 49 = x^2 - 49
Answer:
23. $ 62.76 to the nearest cent
$63.00 to the nearest dollar
24. $ 38.42 to the nearest cent
$38.00 to the nearest dollar
Step-by-step explanation:
When we round to the nearest cent we round the second number after the decimal. We look at the third number after the decimal. If it is 5 or above we round up.
When we round to the nearest dollar, we round the number befroe the decimal. We look at the number after the decimal. If it is 5 or above we round up.
23. $62.756 we round the 5 so we look at the 6 6>= 5 so we round up
$ 62.76 to the nearest cent
$62.756 we round the 2 so we look at the 7 7>= 5 so we round up
$63.00 to the nearest dollar
24. $38.415 we round the 1 so we look at the 5 5>= 5 so we round up
$ 38.42 to the nearest cent
$38.415 we round the 8 so we look at the 4 4< 5 so we leave alone
$38.00 to the nearest dollar
length = 12 yd
width = 10 yd
height = 12 yd
diagonal = 19.697715603592 yd
total surface area = 768 yd2
lateral surface area = 528 yd2
bottom surface area = 120 yd2
volume = 1440 yd3
By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
<h3>What is
sequence ?</h3>
Sequence is collection of numbers with some pattern .
Given sequence

We can see that

and

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2
Now
term of this Geometric progression can be written as

So summation of 15 terms can be written as

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is
To learn more about Geometric progression visit : brainly.com/question/14320920
Given that,
The camera sights the stadium at a 7 degree angle of depression.
The altitude of the blimp i slide 300 m.
To find,
The line of sight distance from the camera to the stadium.
Solution,
If we consider a right angled triangle. Let x is its hypotenuse i.e. the line of sight distance from the camera to the stadium. Using trigonometry :

So, the line of sight is at a distance of 2461.65 m from the camera to the stadium.