Answer:
The lower bound is, 
and the upper bound is 
.
Step-by-step explanation:
Let the random variable <em>X</em> follows a normal distribution with mean <em>μ </em>and standard deviation <em>σ</em>.
The the random variable <em>Z, </em>defined as 
is standardized random variable also known as a standard normal random variable. The random variable 
.
The standard normal random variable has a symmetric distribution.
It is provided that 
.
Determine the upper and lower bound as follows:
![P(-z\leq Z\leq z)=0.51\\P(Z\leq z)-P(Z\leq -z)=0.51\\P(Z\leq z)-[1-P(Z\leq z)]=0.51\\2P(Z\leq z)-1=0.51\\2P(Z\leq z)=1.51\\P(Z\leq z)=0.755](https://tex.z-dn.net/?f=P%28-z%5Cleq%20Z%5Cleq%20z%29%3D0.51%5C%5CP%28Z%5Cleq%20z%29-P%28Z%5Cleq%20-z%29%3D0.51%5C%5CP%28Z%5Cleq%20z%29-%5B1-P%28Z%5Cleq%20z%29%5D%3D0.51%5C%5C2P%28Z%5Cleq%20z%29-1%3D0.51%5C%5C2P%28Z%5Cleq%20z%29%3D1.51%5C%5CP%28Z%5Cleq%20z%29%3D0.755)
Use a standard normal table to determine the value of <em>z.</em>
The value of <em>z</em> such that P (Z ≤ z) = 0.755 is 0.69.
The lower bound is, and the upper bound is .
105 Animals....You know that because when you add together the head & feet that's adding all the animals together to get the total number of animals
Add the two functions together to get
7y=-3
y=-3/7
Then plug in y to either function to solve for x, I’ll just use the left one
15(-3/7)-9x=-9
-45/7-9x=-9
-9x=-18/7
x=18/7/9
x=2/7
Answer:
- g = -1110p +4300.9
- 804 gallons
Step-by-step explanation:
a) Price is the independent variable, so the data we are given can be written as ...
(price, gallons) = (2.99, 982) and (2.79, 1204)
Using the 2-point form of the equation for a line, we have ...
g = (g2 -g1)/(p2 -p1)(p -p1) +g1
g = (1204 -982)/(2.79 -2.99)(p -2.99) +982
g = -1110(p -2.99) +982 = -1110p +4300.9
g = -1110p +4300.9
__
b) When p = 3.15, the predicted sales volume is ...
g = -1110(3.15) +4300.9 = 804.4
Weekly sales are predicted to be 804 gallons at a price of $3.15.
Answer:
(2,6)
Step-by-step explanation:
