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e-lub [12.9K]
3 years ago
15

Jaron paid $13.80 for 5 tickets to the game. At the same rate, how much would 3 tickets cost? *

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

it will cost 8.28

Step-by-step explanation:

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Only answer if u know the answer ​
Dmitriy789 [7]

Answer:

Angle C = 142 degrees

Step-by-step explanation:

A+B = 90

B+C = 180

Rearrange first equation to get B = 90-A

Plug this into the second equation:

90-A + C = 180

C = A + 90

Plug in A, C = 52 + 90 = 142

8 0
2 years ago
Rosalie earns extra money by working as a babysitter over the weekend. She charges $10 to drive to the home and an additional $8
Irina18 [472]
Input value= number of hours babysat, output value= how much money you get.
5 0
3 years ago
Dilly is 7 years younger than Dally. In 4 years time she will be half Dally’s age. What is the sum of their ages now?
Step2247 [10]

Answer:

<u>The sum of their ages now is 13</u>

Step-by-step explanation:

Dally's age = x

Dilly's age = x - 7

In 4 years time Dilly will be half Dally’s age, therefore:

Dilly's age plus four equals to half of Dally’s age plus four,

replacing with the values and variables we know:

x - 7 + 4 = (x + 4) /2

x - 3 = (x + 4) /2

2x - 6 = x + 4 (Multiplying by 2 at both sides)

2x - x = 4 + 6 (Like terms)

x = 10 ⇒ x - 7 = 3

<u>The sum of their ages now is 13 (10 + 3)</u>

4 0
3 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
In art class,Kerion is coloring a pattern where half of the squares on her paper are being colored blue. Of the blue squares,1/3
kolbaska11 [484]
100% of Kerion's paper squares are:
 (100% / 100%) = 1
 Half of the squares of your paper are colored blue:
 (1) / (2) = 1/2
 Of the blue squares, 1/3 of them will also have stripes:
 (1/2) * (1/3) = 1/6
 answer
 A fraction of (1/6) squares will be blue with strips
7 0
3 years ago
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