3 years ago

Find the value of the expression (3x−12)+12(xy−10)(3x-12)+12(xy-10) for x=4x=4 and y=6y=6 .

1 answer:

6 0

(3x-12)+12(xy-10), x=4, y=6
(3(4)-12)+12((4)(6)-10)
(12-12)+12(24-10)
0+12(14)
12*14=168

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