Answer:
its congruent because of the lines
Answer:
C. 364.4
E. 14
F. 21
G. 96°
VK = VY+YK by the segment addition postulate. Basically adding two segments along a straight line forms a longer segment. In this case, VY and YK combine to form VK
Since VK = x and VY = 22, this means...
VK = VY+YK
x = 22+YK
x-22 = YK
YK = x-22
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Notice the arc marks where the point T is located. These markings tell us that the two angles VTY and YTK are congruent angles. Because of this, we can use the angle bisector theorem which says that the ratio of the corresponding sides are congruent.
In short, we can form this ratio
VT/VY = KT/KY
which is the ratio of the side adjacent to the angle, to the side opposite the angle
Plug in the given values and solve for x
VT/VY = KT/KY
77/22 = 87.5/(x-22)
77(x-22) = 22*87.5
77(x-22) = 1925
77x-77*22 = 1925
77x-1694 = 1925
77x = 1925+1694
77x = 3619
x = 3619/77
x = 47
Answer: 47
Answer:
85 cm²
Step-by-step explanation:
The base is a square with side length 5 cm. The area of this base is
A = s² = (5 cm)² = 25 cm².
If the slant height of each lateral face of the pyramid is 6 cm, then we can find the area of each such face using the area-of-a-triangle formula,
A = (1/2)(base)(height), which here is
A = (1/2)(5 cm)(6 cm) = 15 cm² per lateral side.
The total area of these sides is 4(15 cm²) = 60 cm².
Then the total surface area of the pyramid is A = 60 cm² + 25 cm² = 85 cm².
