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Paraphin [41]
3 years ago
9

In an EFE​ Matrix, how much more important is a weight of 0.20 than a weight of​ 0.15? A. ​50% B. ​33% C. ​25% D. ​.05% E. ​5.0%

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0

Answer:  B. ​33%

Step-by-step explanation:

  • In Mathematics , a percentage is basically a process of dividing the numerator by the denominator , then multiply the answer by 100.

We use Mathematical Formula : \dfrac{\text{Difference between the Weight of 0.20 and Weight of 0.15 }}{\text{Weight of 0.15}}\times100

Since , Difference between the Weight of 0.20 and Weight of 0.15  = 0.20-0.15=0.05

Then, substitute the value in formula , we get

=\dfrac{0.05}{0.15}\times100\\\\=\dfrac{5}{15}\times100\\\\ \dfrac{100}{3}\%\approx33\%

Hence, the weight of 0.20 is 33% more important than a weight of​ 0.15.

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Answer:

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Step-by-step explanation:

A line that is perpendicular to it has a slope that is an opposite reciprocal, which in this case is -1/3.  Now you use point slope form which is y-y1=m(x-x1) that would be y+5=-1/3(x-6).  Distribute the -1/3 and get y+5= -1/3 x+ 2.  Subtract 5 from both sides and get y=-1/3 x - 3

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y=1/3x+4

Step-by-step explanation:

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3 years ago
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Answer:

3/5 would be your answer.

Step-by-step explanation:

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hope it helps!

5 0
3 years ago
Read 2 more answers
The area of the regular pentagon is 6.9 cm2. What is the perimeter? 2 cm 5 cm 10 cm 20 cm
disa [49]

Given

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Formula

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As given in the question

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now equating the area value with the area formula.

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Now put

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put in the above equation

\frac{6.9\times 4}{\sqrt{5(5+2\times2.24)}}=a^{2}\\\frac{27.6}{\sqrt{47.4}}=a^{2}\\\frac{27.6}{6.88}=a^{2}

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As perimeter  represented the sum of all sides.

i.e regular pentagon have five sides of equal length.

Thus

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therefore the perimeter of the regular pentagon = 10cm

option c is correct

Hence proved









3 0
3 years ago
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