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3 years ago

How many ways can 40 students be divided equally between 5 teachers

Mathematics

2 answers:

zlopas [31]3 years ago

7 0

Answer:

8 if u divide 40/5=8

u can also check ur work by multiplying 8*5=40

hope this helps :3

Sergeeva-Olga [200]3 years ago

4 0

Answer: 8

Step-by-step explanation: do 40 divided by 5 and get 8

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PLEASE HELP DUE TODAY !

igor_vitrenko [27]

Answer:

let x be chips and y be sodas

8x + 4y = 5 ---> for the first hint

4x + 8y = 7------> second hint

0.25 cents is how much chips costs

and 0.75 cents is how much sodas costs

5 0

3 years ago

Read 2 more answers

The nth term of a sequence is 60-8n. Find the largest number in this sequence.

natka813 [3]

Answer:

Step-by-step explanation:

1st term is =60-8=52

a2=60-16=44

a3=60-24=36

a4=60-32=28

a5=60-40=20

a6=60-48=12

....

sI the terms are 52,44,36,28, 20,12,4,-4,-12....

so the largest term is 52

6 0

2 years ago

Take away 8 from 5 times m

ch4aika [34]

Answer:

5m-8

Step-by-step explanation:

7 0

3 years ago

Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8

Kitty [74]

Substitute $z=\ln x$ , so that

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}$

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)$

Then the ODE becomes

$x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0$
$\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0$

which has the characteristic equation $r^2+1=0$ with roots at $r=\pm i$ . This means the characteristic solution for $y(z)$ is

$y_C(z)=C_1\cos z+C_2\sin z$

and in terms of $y(x)$ , this is

$y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)$

From the given initial conditions, we find

$y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1$
$y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8$

so the particular solution to the IVP is

$y(x)=\cos(\ln x)+8\sin(\ln x)$

4 0

3 years ago

A contractor is building a fenced-in area at a daycare. The area will be rectangular with the length of its base equal to half t

AlladinOne [14]

Answer:

The length of fencing will be $300\ ft$