All categories

3 years ago

PLEASE HELP ME!!! ILL GIVE BRAINLIEST TO RIGHT ANSWER

Mathematics

1 answer:

11111nata11111 [884]3 years ago

7 0

Answer:

792m^2

Step-by-step explanation:

Seperate your 2 rectangles

Large one is 18*30

Small one (60-18)*6

18*30 = 540m^2

42*6=252m^2

You might be interested in

What goes in the boxes ig?

lana [24]

To convert 1.07 to a fraction, multiply it by 100.

1.07 * 100 = 107

So the percent equivalent of 1.07 is 107%.

Just put 1.07 over 100 to turn it into a fraction.

107/100 would be the fraction equivalent.

7 0

2 years ago

The sum of two numbers is 52. The larger number is 8 more than the smaller number. What are the numbers?

iVinArrow [24]

Answer:

The smaller number is 22

The larger number is 30

Step-by-step explanation:

L + S = 52

L = S + 8

Set both equations equal to L.

S + 8 = -S + 52

+S +S

2S + 8 = 52

- 8 - 8

2S = 44

S = 22

To find the larger number, plug 22 in as S into the equations.

L = 30

3 0

3 years ago

Which test point holds true for the inequality 3/2y-2x>=1? Where does the shaded area lie for this inequality? The test point

Tanya [424]

The test That holds true for this inequality is given as 1/4 and 1

<h3>How to solve for the inequality</h3>

3/2 y - 2x > 1

The goal is to make y the subject

then

3/2 y > 2x + 1

We have to divide through the equation by 3/2

Such that y > 4/3 x + 2/3

Read more on inequality here: brainly.com/question/25275758

#SPJ1

8 0

2 years ago

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

3 years ago

Read 2 more answers

Sara works for a hair salon and receives tips from her customers. The weekly tips

Monica [59]

Answer:

mean: 107.86

median: 100

range: 140

mode: 100

Step-by-step explanation:

3 0

2 years ago