Question

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Answer 1

Answer:

see below

Step-by-step explanation:

i.

= √(3 + 4i)

= 2 + i

ii.

= √(-8 + 6i)

= √2(-4 + 3i)

iii.

= √(-40 - 42i)

= √-2(20 + 21i)

iv.

= √i

= √i

v.

= $\sqrt{\frac{2 + 3i}{5 - 4i} } +\sqrt{\frac{2-3i}{5+4i} }$

= $\sqrt{\frac{-2+23i}{41} } +\sqrt{\frac{2-3i}{46} }$