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2 years ago

Need more points ??? solve this .....only first part for 50 points .....and follow me also!

Mathematics

1 answer:

leonid [27]2 years ago

7 0

Answer:

see below

Step-by-step explanation:

= √(3 + 4i)

= 2 + i

ii.

= √(-8 + 6i)

= √2(-4 + 3i)

iii.

= √(-40 - 42i)

= √-2(20 + 21i)

iv.

= √i

= $\sqrt{\frac{2 + 3i}{5 - 4i} } +\sqrt{\frac{2-3i}{5+4i} }$

= $\sqrt{\frac{-2+23i}{41} } +\sqrt{\frac{2-3i}{46} }$

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Tems11 [23]

The inequality for this situation is given by 50 + p > 85

<h3>What is an inequality?</h3>

An inequality is an expression that shows the relationship between two or more numbers and variables.

Let p represent number of pages from Monday to Friday.

Jerome wants to have read at least 85 pages by the end of the day on Friday, hence:

50 + p > 85

The inequality for this situation is given by 50 + p > 85

Find out more on inequality at: brainly.com/question/24372553

7 0

2 years ago

Hank has an old oil barrel he will use for a garbage can. The oil barrel is 84 centimeters in diameter and 150 centimeters in he

GREYUIT [131]

The answer to this question is going to be letter B

3 0

3 years ago

The area of a rhombus is 72 m2. One diagonal is 18m. Find the other diagonal.

miskamm [114]

Answer:

Other diagonal is 8 m

Step-by-step explanation:

area of rhombus = 72 m²

½ × diagonal 1 × diagonal 2 = 72

½ × 18 × d2 = 72

9 × d2 = 72

d2 = 72/9

d2 = 8

7 0

1 year ago

Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?

Bogdan [553]

Step-by-step explanation:

$\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}$

$\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}$

$\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}$

$\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}$

Taking sin²θ common in both numerator & denominator, We get :

$\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}$

$\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}$

$\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}$

$\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}$

$\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}$

$\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}$

$\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}$

$\mathsf{\implies \dfrac{5 - 1}{5 + 1}}$

$\mathsf{\implies \dfrac{4}{6}}$

$\mathsf{\implies \dfrac{2}{3}}$

Hence, option (a) 2/3 is your correct answer.

3 0

2 years ago

Use suitable Identities and find ●( X - 5 ) ( x-5 ) ●( 3x +2 ) (3x -2 ) ●( 1+x )(1+x)

Nonamiya [84]

Answer:

$.$

Step-by-step explanation:

<h2>IdEnTiTy UsED</h2>

${x}^{2} - {y}^{2} = (x + y)(x - y)$

$(x - 5)(x - 5)$

=(x-5)²

$(3x - 2)(3x + 2)$

${(3 x)}^{2} - {(2)}^{2}$

$= 9 {x}^{2} - 4$

$(1+x)(1+x)$

= (1+x)²

6 0

3 years ago

Need more points ??? solve this .....only first part for 50 points .....and follow me also!​

Need more points ??? solve this .....only first part for 50 points .....and follow me also!