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3 years ago

PLS HELP IVE BEEN ASKING FOR 3 1/2 DAYS IM ABOUT TO FAIL 7th GRADE ITS OVERDUE WILL GIVE BRAINLIEST IF YOU ANSWER THIS TYSM

Mathematics

2 answers:

Nataliya [291]3 years ago

5 0

Answer:18 days

Step-by-step explanation:

Elanso [62]3 years ago

5 0

Answer:

18 days to consume the apple

Step-by-step explanation: 18 because it takes 3 days for a half so six days equals 1 whole apple multiply that by 3 an you'll get 18

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Blood is a buffer solution. When carbon dioxide is absorbed into the bloodstream, it produces carbonic acid and lowers the pH. T

Irina18 [472]

Answer:

x ≅ 20.10 torr

Step-by-step explanation:

Given that the equation which models blood pH in the question is;

pH(x)=6.1+log(800/x)

where;

pH = 7.7

x = partial pressure of carbon dioxide in arterial blood, measured in torr.

we are asked to find (x)

In order to do that, we use the given equation:

pH(x)=6.1+log(800/x)

since pH = 7.7

7.7 = 6.1 + log (800/x)

7.7 - 6.1 = log (800/x)

1.6 = log (800/x)

$10^{1.6}= \frac{800}{x}$

$x= \frac{800}{10^{1.6}}$

x = 20.09509145

x ≅ 20.10 torr

4 0

3 years ago

A student's tuition was $5530. A loan was obtained for 4/7 of the tuition. How much was the loan?

Sophie [7]

Multiply the two numbers to find the amount of the loan.

5530/1* 4/7= 22120/7= 3160

Final answer: $3,160

5 0

3 years ago

30 POINTS!!! Which choice is equivalent to the fraction below when x is greater than or equal to 3?

Mashcka [7]

Answer: C.

$\frac{9}{\sqrt{x} -\sqrt{x-3} }=\frac{9(\sqrt{x} +\sqrt{x-3} )}{x-(x-3)}=\frac{9(\sqrt{x} +\sqrt{x-3} )}{3}=3(\sqrt{x} +\sqrt{x-3})$

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the function with its graph

MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

$f(x)=(x-2)^{2}+1$

45)

The function g(x) is given by:

$g(x)=f(x-1)$

using f(x) we can find f(x-1)

$g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1$

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

$g(x)'=2(x-3)$

$2(x-3)=0$

$x=3$

Puting it on g(x) we will get y value.

$y=g(3)=(3-3)^{2}+1$

$y=g(3)=1$

Then, the minimum point of this function is (3,1) and it corresponds to (A)

46)

Let's use the same method here.

$g(x)=f(x+2)$

$g(x)=((x+2)-2)^{2}+1$

$g(x)=(x)^{2}+1$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2x$

$0=2x$

$x=0$

Evaluatinf g(x) at this value of x we have:

$g(0)=(x)^{2}+1$

$g(0)=1$

Then, the minimum point of this function is (0,1) and it corresponds to (C)

47)

Let's use the same method here.

$g(x)=f(x)+2$

$g(x)=(x-2)^{2}+1+2$

$g(x)=(x-2)^{2}+3$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}+3$

$g(2)=3$

Then, the minimum point of this function is (2,3) and it corresponds to (B)

48)

Let's use the same method here.

$g(x)=f(x)-3$

$g(x)=(x-2)^{2}+1-3$

$g(x)=(x-2)^{2}-2$

Let's find the first derivative and equal to zero to find x and y minimum value.

$g'(x)=2(x-2)$

$0=2(x-2)$

$x=2$

Evaluatinf g(x) at this value of x we have:

$g(2)=(2-2)^{2}-2$

$g(2)=-2$

Then, the minimum point of this function is (2,-2) and it corresponds to (D)

I hope it helps you!

8 0

3 years ago

GIVING BRAINLIEST FOR BEST ANSWER! Write a story that could represent this math problem.

STatiana [176]

Answer:

I have zero clue what the hell this is supposed to be

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers