Answer:
The container is filled to 87.5% of the maximum capacity.
Step-by-step explanation:
Given
Maximum capacity of container = m = 64 ounces
Filled capacity=> as it is 8 less than maximum capacity = 64-8 = 56 ounces
The container is 56 ounces full.
To find the percentage:

Hence,
The container is filled to 87.5% of the maximum capacity.
Answer:
the new perimeter will be 1/3 time the perimeter of the original rectangle
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given

Required
Find

Calculate 
Using tan rule

So:






'
'So:



Answer:
-63
Step-by-step explanation:
Because -9 x 7 = -63. If the signs are different then it will be negative. -9 x 7 = -63 is the same like 9 x 7 = 63. I hope this answer your question!