Find the area of a cross section parallel to the base of a cylinder with a radius of 2.5 cm and a height of 12 cm
1 answer:
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To start to solve this problem, we need to know what vertex form is. The vertex form of a parabola is. The vertex form of a parabola is a(x-h) + k, where k is the vertical shift, h is the horizontal shift, and a is the value that tells the stretch.
To start to solve this equation, we want to start to create a difference of two squares.
y = 2(x²+x) We do this step to make the x² have a coefficient of 1
Now, we want to complete the square. To complete the square, we take 1/2 of the coefficient of x, and then square that.
1/2 * 1/2 = 1/4, and 1/4²=1/16
That means that we need to add 1/16 inside and outside the parenthesis.
We get:
y = 2(x²+1/2x + 1/16) - 1/16*2
We do -1/16*2 on the outside because since we added it inside the parenthesis, we need to take it away somewhere else (if that makes sense). The two is there because there is a two in front of the parenthesis.
We get:
y = 2(x+1/4)² - 1/8, by completing the square and simplifying, and this is the final answer.
Answer:
Angle 1 = 108°
Angle 2 = 72°
Angle 3 = 120°
Angle 4 = 96°
Angle 5 = 144°
Step-by-step explanation:
We need to find the measures of the interior angles in a pentagon if the measure of each consecutive angle is in the ratio 9:6:10:8:12.
Let x be the common ratio
So, we can write:
Angle 1 = 9x
Angle 2 = 6x
Angle 3 = 10x
Angle 4 = 8x
Angle 5 = 12x
We know that the <em>sum of all angles of pentagon = 540</em>
So, adding all angles and equal them to 540, we can find value of x
So, we get the value of x: x=12
Now, calculating the angles by putting x=12:
Angle 1 = 9x = 9(12) = 108°
Angle 2 = 6x = 6(12) = 72°
Angle 3 = 10x = 10(12) = 120°
Angle 4 = 8x = 8(12) = 96°
Angle 5 = 12x= 12(12) = 144°
