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3 years ago

Solve by factoring 3x²-13x=10

Mathematics

1 answer:

Dimas [21]3 years ago

7 0

Answer:

x=5, -2/3

Step-by-step explanation:

3x^2-13x=10

3x^2-13x-10=0

factor out,

(3x+2)(x-5)=0,

zero property,

3x+2=0, x-5=0,

3x=0-2=-2

3x=-2, x=-2/3

x=0+5=5, x=5

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Answer:

See answers and explanations below (along with a visual graph)

Step-by-step explanation:

For the function $y=acos(b(x+c))+d$ :

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Phase shift: $\frac{-c}{b}$

Vertical shift: $d$

Therefore, for $y=2cos(\frac{2}{3}(\theta+\pi))-1$ :

Amplitude: $|a|=|2|=2$ , which is 2 units above and below the midline (see d)

Period: $\frac{2\pi}{|b|}=\frac{2\pi}{|\frac{2}{3}|}=\frac{2\pi}{\frac{2}{3}}=3\pi$ , so the cycle will repeat every 3π units

Phase shift: $\frac{-c}{b}=\frac{-\frac{2\pi}{3} }{\frac{2}{3} }=-\pi$ , or π units to the left

Vertical shift: $d=-1$ , or 1 unit down

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3 years ago

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Answer:

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Step-by-step explanation:

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kicyunya [14]

Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20" id="TexFormula1" title=" \sqrt[3]{x - 1} " alt=" \sqrt[3]

shusha [124]

So the -1 is under the check mark too?

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