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2 years ago

If the side length of a square is 7.2 inches what is the area of the square

Mathematics

1 answer:

algol [13]2 years ago

7 0

A = l²

A = 7.2²

A = 51.84

51.84 inches

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Enter the terms and the coefficients of the expression.

Alja [10]

Answer:

terms: 3x,+90y,-70

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3 years ago

PLZZ HELP bubba biked 19 kilometers how far did he bike in miles? A mile is approximately 1.6 kilometers Round to the nearest te

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2 years ago

Read 2 more answers

Orthogonalizing vectors. Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, a

jeka57 [31]

Answer:

$\\ \gamma= \frac{a\cdot b}{b\cdot b}$

Step-by-step explanation:

The question to be solved is the following :

Suppose that a and b are any n-vectors. Show that we can always find a scalar γ so that (a − γb) ⊥ b, and that γ is unique if $b \neq 0$ . Recall that given two vectors a,b a⊥ b if and only if $a\cdot b =0$ where $\cdot$ is the dot product defined in $\mathbb{R}^n$ . Suposse that $b\neq 0$ . We want to find γ such that $(a-\gamma b)\cdot b=0$ . Given that the dot product can be distributed and that it is linear, the following equation is obtained

$(a-\gamma b)\cdot b = 0 = a\cdot b - (\gamma b)\cdot b= a\cdot b - \gamma b\cdot b$

Recall that $a\cdot b, b\cdot b$ are both real numbers, so by solving the value of γ, we get that

$\gamma= \frac{a\cdot b}{b\cdot b}$

By construction, this γ is unique if $b\neq 0$ , since if there was a $\gamma_2$ such that $(a-\gamma_2b)\cdot b = 0$ , then

$\gamma_2 = \frac{a\cdot b}{b\cdot b}= \gamma$

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3 years ago

You spin a spinner, flip a coin, then spin the spinner again. Find the probability of spinning an odd number, flipping heads, th

vovangra [49]

Answer:

1/8

Step-by-step explanation:

you would multiply 5/10x1/2x5/1o. Since the spinner has 10 areas, 5 of them are odd and 5 are even and a coin has 2 sides, head or tails.

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3 years ago

I don’t really get this question so if anyone knows it please help

Mars2501 [29]

Answer:

$116.82\:\text{square inches}$

Step-by-step explanation:

The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is $10^2=100\:\mathrm{in^2}$ .

The area of a triangle is given by $\frac{1}{2}\cdot b\cdot h$ . Since the problem states that the overlapping squares are congruent, both legs of the triangle will be $2.9$ and intersect at a $90^{\circ}$ angle.

Thus, the sum of all four triangles is $\frac{1}{2}\cdot 2.9\cdot 2.9\cdot 4=16.82\:\mathrm{in^2}$ .

Therefore, the area of the window is:

$100+16.82=\boxed{116.82\:\mathrm{in^2}}$

3 0

3 years ago