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DerKrebs [107]
2 years ago
9

Find the midpiont between y and 31 is -5 find y

Mathematics
2 answers:
LenKa [72]2 years ago
5 0

Answer:

y=-41

Step-by-step explanation:

\frac{y+31}{2} =-5\\y+31=-5 \times 2\\y+31=-10\\y=-10-31\\y=-41

SCORPION-xisa [38]2 years ago
5 0
Y=41 would be your correct answer.
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i think its 8

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RUDIKE [14]

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19

Step-by-step explanation:

I put it in my calculator

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What are the values for matrix A?: 1 2 3 4 1 3 4 5 6 7 8 Noo 4 1 0 0 9 6 7 8 10 12 14 15 16 13 14 14 15 16​
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Since the values are the same on both sides the matrix value is a=1
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3 years ago
Can you see an easy way to work out the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%201%5E3%20%2B%202%5E3%20%2B%203%5E
Lina20 [59]

We have the sum of cubes identity

a^3 + b^3 = (a + b) (a^2 - ab + b^2)

and observing that 1 + 4 = 2 + 3, we have

1^3 + 4^3 = (1 + 4) (1^2 - 4 + 4^2) = 5 \times 13

and

2^3 + 3^3 = (2 + 3) (2^2 - 6 + 3^2) = 5 \times 7

Then

\sqrt{1^3+2^3+3^3+4^3+5^3} = \sqrt{5\times13 + 5\times7 + 5\times5^2} = \sqrt{5 \times (20 + 25)} \\\\ ~~~~~~~~ = \sqrt{5^2 \times (4 + 5)} = \sqrt{5^2\times9} = \sqrt{5^2\times3^2} = 5\times3 = \boxed{15}

Alternatively, we have the well-known sum of cubes formula

\displaystyle \sum_{i=1}^n i^3 = \frac{n^2(n+1)^2}4

The sum under the square root is this sum with n=5. Then

1^3+2^3+3^3+4^3+5^3 = \dfrac{5^2\times6^2}4 = 225 = 15^2

and so the square root again reduces to 15.

5 0
2 years ago
In the following equation, f(x)=2x +7, what is f(-3)?
Helen [10]

Answer:

f(-3) = 1

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 2x + 7

f(-3) is x = -3

<u>Step 2: Evaluate</u>

  1. Substitute:                   f(-3) = 2(-3) + 7
  2. Multiply:                       f(-3) = -6 + 7
  3. Add:                             f(-3) = 1
5 0
3 years ago
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