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Nuetrik [128]
3 years ago
9

A frame of width a surrounds a 5 by 7 inch photograph. Find the expression that represents the area of the frame in terms of a.

Mathematics
1 answer:
Arada [10]3 years ago
4 0
See diagram
totalarea=totallengtht times totalwidth=(2a+5) times (2a+7)=4a²+24a+35

minus original aera
which is 5 by 7 which is 35

4a²+24a+35-35=4a²+24a


3rd option I think, can't tell which is which

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8 0
4 years ago
96 fluid ounce is greater than,less than or equal to 13 c
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The answer is 96 F,O, >,< or = 13 C. Hop this helps.

7 0
3 years ago
The sum of three times a first number and twice a second number is 14. If the second number is subtracted from twice the first n
Yanka [14]
Answer: 4, 1

Step-by-Step Explanation:

Let the First Number be ‘x’
Let the Second Number be ‘y’

Framing 2 Equations :-

=> 3x + 2y = 14 (Eq. 1)
=> 2x - y = 7 (Eq. 2)

Multiplying Eq. 2 by 2 :-

=> 4x - 2y = 14 (Eq. 3)

Adding Eq. 1 and Eq. 3 we get :-

7x = 14 + 14
7x = 28
x = 28/7
=> x = 4

Therefore, x = 4

Substitute value of ‘x’ in Eq. 1 :-

3x + 2y = 14
3(4) + 2y = 14
12 + 2y = 14
2y = 14 - 12
2y = 2
y = 2/2
=> y = 1

Therefore, y = 1

Hence,
First Number = 4
Second Number = 1
5 0
2 years ago
The width of a rectangler figure is 5 units smaller than its length. if its area is 14 units square. find its dimensions
oksano4ka [1.4K]

W = L - 5

A = W.L

14 = (L - 5).L

14 = L² - 5L

L² - 5L -14 =0

(L - 7)(L + 2) = 0 {factorized}

L = 7 / L = -2

In this case L would be equal to 7 because a length of anything can't be a negative number

Therefore, W = 2

Answer : Length = 7   Width = 2


6 0
3 years ago
Best answer gets the brainliest!<br> Find $a/b$ when $2\log{(a -2b)} = \log{a} + \log{b}$.
andrey2020 [161]

By some properties of logarithms, rewrite the equation as

2\log(a-2b) = \log(a) + \log(b) \\\\ \log(a-2b)^2 = \log(ab)

so that

(<em>a</em> - 2<em>b</em>)² = <em>ab</em>

Expand the left side:

<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>

Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :

<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0

<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get

<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0

Factorize and solve for <em>a</em>/<em>b</em> :

(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0

==>   <em>a</em>/<em>b</em> = 4   or   <em>a</em>/<em>b</em> = 1

However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with

<em>a</em>/<em>b</em> = 4

5 0
3 years ago
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