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The answer is 96 F,O, >,< or = 13 C. Hop this helps.
Answer: 4, 1
Step-by-Step Explanation:
Let the First Number be ‘x’
Let the Second Number be ‘y’
Framing 2 Equations :-
=> 3x + 2y = 14 (Eq. 1)
=> 2x - y = 7 (Eq. 2)
Multiplying Eq. 2 by 2 :-
=> 4x - 2y = 14 (Eq. 3)
Adding Eq. 1 and Eq. 3 we get :-
7x = 14 + 14
7x = 28
x = 28/7
=> x = 4
Therefore, x = 4
Substitute value of ‘x’ in Eq. 1 :-
3x + 2y = 14
3(4) + 2y = 14
12 + 2y = 14
2y = 14 - 12
2y = 2
y = 2/2
=> y = 1
Therefore, y = 1
Hence,
First Number = 4
Second Number = 1
W = L - 5
A = W.L
14 = (L - 5).L
14 = L² - 5L
L² - 5L -14 =0
(L - 7)(L + 2) = 0 {factorized}
L = 7 / L = -2
In this case L would be equal to 7 because a length of anything can't be a negative number
Therefore, W = 2
Answer : Length = 7 Width = 2
By some properties of logarithms, rewrite the equation as

so that
(<em>a</em> - 2<em>b</em>)² = <em>ab</em>
Expand the left side:
<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>
Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :
<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0
<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get
<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0
Factorize and solve for <em>a</em>/<em>b</em> :
(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0
==> <em>a</em>/<em>b</em> = 4 or <em>a</em>/<em>b</em> = 1
However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with
<em>a</em>/<em>b</em> = 4