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2 years ago

5

Please add the numbers to the graph and show the work on a paper and post it please if you do not know the answer do not comment

thank u.

1 answer:

tresset_1 [31]2 years ago

8 0

Answer:

merry crisis

Step-by-step explanation:

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Find f(x)+g(x), given f(x)=x^2-8 and g(x)=-2-x^2

Gnoma [55]

$\left(x^2-8\right)+\left(-2-x^2\right)=-10$

$\left(x^2-8\right)+\left(-2-x^2\right)$

$=x^2-8-2-x^2$

$=x^2-x^2-8-2$

$=-8-2$

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2 years ago

2x-8y=6<br> y=-7- x<br> what are the coordinates

goblinko [34]

2x-8(-7-x)=6
2x+56+8x=6
10x=-50
x=-5

y=-7-(-5)
y=-2

(-5,-2)

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3 years ago

The radius of a circle is 8 feet. What is the area of sector bounded by a 90° arc?

Lera25 [3.4K]

Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.

The radius is given by, r = 8 ft, therefore, the area of the full circle is,

$\begin{gathered} A=\pi\times r^2 \\ A=3.14\times8^2=200.96ft^2 \end{gathered}$

Therefore, the area of the sector is,

$A^{\prime}=\frac{1}{4}\times200.96ft^2=50.24ft^2$ $\begin{gathered} A^{\prime}=\frac{\theta}{360}\times\pi\times r^2 \\ \text{ =}\frac{\text{90}}{360}\times\pi\times8^2 \\ \text{ =}\frac{1}{4}\pi\times64=16\pi \end{gathered}$

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1 year ago

Four circles, each with a radius of 2 inches, are removed from a square. What is the remaining area of the square? (16 – 4π) in.

anyanavicka [17]

Since 4 circles are circumscribed by a square, then the side length of the square is 8

So the area of the square is 8^2 = 64

The area of 4 squares is 4 * pi*2^2 = 16pi

So the answer will be 64 - 16pi

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2 years ago

Read 2 more answers

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alukav5142 [94]

16)

s^1/4 * s^1/4 * s^1/4 * s^1/4 = s^(1/4 + 1/4+1/4+1/4) = s^4/4 = s

Answer is s

15) Answer is 1. (because any number to the 0 exponent is equal 1 , except 0)

17)

= (t^3/6)^2 = t^6/6 = t

Answer is t

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2 years ago