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3 years ago

The Student Athletes Club has a

Mathematics

1 answer:

devlian [24]3 years ago

3 0

Answer:

Step-by-step explanation:

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Please help!!! asap!!!

quester [9]

Answer:

x = 11 cos 22 = 11 * .927 = 10.2

5 0

2 years ago

Please help

oksian1 [2.3K]

Answer:

1: 11√3 - 7√6

2: 11√3 - 7√6

3: -9

4:12

Step-by-step explanation:

To add radicals they need to have the same radical part for the first one we have

7√3- 4√6 + √48 - √54

We can simplify the last two into 4√3 and 3√6

So we have 7√3 - 4√6 + 4√3 - 3√6

adding similar radicals we get

11√3 - 7√6

For the second one we have 11√3 - 7√6

There's nothing we can do from here so keep that as your answer

This one is quite easy -3√9

square root of 9 is 3

so we have -3*3 which is -9

next is

4√9

same deal as the one before

3*4=12

5 0

2 years ago

Read 2 more answers

Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were

S_A_V [24]

Answer:

Step-by-step explanation:

You need to set up and solve a system of linear equations here.

Let s and a represent the number of students and adults respectively.

Then s + a = 9, and s = 9 - a.

Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

Total cost of the tickets was then ($8/adult)(a) + ($5/student)(s) = $60.

Then our system of linear equations is:

8a + 5s = 60

a + s = 9, or s = 9 - a. Substituting 9 - a for s, we get:

8a + 5(9 - a) = 60.

Then 8a + 45 - 5a = 60, or 3a = 15.

Solving for a, we get a = 5.

Solving for s using s = 9 - a, we get s = 9 - 5, or s = 4.

There were 5 adults in the group (and 4 students).

3 0

3 years ago

I need help with this question i dont understand it

RUDIKE [14]

The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
$\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2} }$
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
$\sqrt{(3-2) ^{2}+(4-3) ^{2} }$
which simplifies to
$\sqrt{(1 )^{2}+(1) ^{2} }$ which is $\sqrt{2}$
So that is the length of both MN and LM. So far our perimeter is $\sqrt{2} + \sqrt{2}=2 \sqrt{2}$
Now let's use the same formula to find out the length of one of the longer segments:
$\sqrt{(5-3) ^{2} +(3-2) ^{2} }$
which simplifies down to
$\sqrt{(2) ^{2} +(1) ^{2} }$
which is of course $\sqrt{5}$
Since we have 2 of those lengths, $\sqrt{5} + \sqrt{5}=2 \sqrt{5}$
So our perimeter is, in the end, $2 \sqrt{2}+2 \sqrt{5}$
That's the third choice down

7 0

3 years ago

At a sale this week, a suit is being sold for $663. This is a 15% discount from the original price.

nignag [31]

Answer:

563.55

Step-by-step explanation:

85/100*663=563.55

6 0

3 years ago