Ask question

Ask question

All categories

2 years ago

9

A stack of 500 pieces of paper is 1.875 inches tall.

1 answer:

gtnhenbr [62]2 years ago

8 0

If there were 1000 sheets of paper, then the thickness of each sheet would be 1.875 in divided by 1000.

1.875/1000 = 0.001875

Since there are 500 sheets of paper, each one is twice as thick as 0.001875, so each sheet is 0.00375 inches thick. 0.015 is much greater than 0.00375, so it must be incorrect.

You might be interested in

If you get this right I will mark you as a brainliest

storchak [24]

CL will always be the same as LD, the CD line is perpendicular to AB where the L is, so, the extreme points of CD will always be in the same distance of L.

8 0

3 years ago

Read 2 more answers

The population of a city is represented by the function p(t)=33,500(1.014)^t where t represents time in years and corresponds to

Anna [14]

Answer:

its B

Step-by-step explanation:

6 0

2 years ago

If anyone would like a quick response to their question im happy to help :) it can be about anything

IgorLugansk [536]

Answer:

I could really use some help on a question that I am struggling with. Can you help? Here it is...

Step-by-step explanation:

What is the interest on $3,500 borrowed for two years at 2.5% interest?

4 0

2 years ago

In the figure below, points A, B, and C are ______ points because they lie on the same line.

Nutka1998 [239]

Answer:

A, B, C are Collinear points

Step-by-step explanation:

5 0

2 years ago

Gavin has $7,500 to invest. He is considering two investment options. Option A pays 4% simple interest. Option B pays 3.15% inte

Leviafan [203]

Solution:

Principal =P= $ 7,500

Option A→(Simple interest)

Rate of interest= R=4%

Time( $T_{1}$ )=4 years

Time( $T_{2}$ )=6 years

Amount= Principal + Interest(Simple or compound interest)

Formula for Simple interest

$S.I=\frac{P\times R\times T}{100}$

$S.I_{1}=\frac{7500 *4*4}{100}=1200\\\\ S.I_{2}=\frac{7500 *4*6}{100}=1800$

Total amount after 4 years when interest is simple= 7500 +1200= $ 8700

Total amount after 6 years when interest is simple= 7500 +1800= $ 9300

Option B

Formula for amount(A) when interest is 3.15% compounded annually.

$A=P*(1+\frac{R}{100})^t$

$A_{4}=7500*(1+\frac{3.15}{100})^4\\\\ A_{4}=7500*(\frac{103.15}{100})^4\\\\ A_{4}=7500*(1.0315)^4\\\\ A_{4}=7500*1.1320\\\\ A_{4}=8490.60$

$A_{6}=7500*(1+\frac{3.15}{100})^6\\\\ A_{6}=7500*(\frac{103.15}{100})^6\\\\ A_{6}=7500*(1.0315)^6\\\\ A_{6}=7500*1.2045\\\\ A_{6}=9033.9286$

Total amount after 4 years when interest is compounded annually=$ 8491 (approx)

Total amount after 6 years when interest is compounded annually=$ 9034(approx)

4 0

2 years ago

Read 2 more answers