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3 years ago

13

Tickets that cost $88 for a professional women’s championship soccer game are offered at a 15% discount. What is the sale price?

1 answer:

RoseWind [281]3 years ago

6 0

Answer:

$74.80

Step-by-step explanation:

10% = 8.8

5% = 4.4

8.8 + 4.4 = 13.2

88 - 13.2 =$74.80

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There is a spinner with 12 equal areas, numbered 1 through 12. If the spinner is spun

Tomtit [17]

Answer:

1/12

Step-by-step explanation:

There is only number between 1 and 12 that is both a multiple of 5 and 2, that being 10. 10 has an equal chance out of all the other numbers that can be spun, and there are 12 numbers, so 10 has a 1/12 chance of being spun.

6 0

3 years ago

Algebra 2 help needed image below

Nookie1986 [14]

Answer:

8x + 100

Step-by-step explanation:

Your answer is correct! But because the equation is already set to "y =", you do not need the "f(x)" in your equation.

7 0

1 year ago

Two shooters, Rodney and Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark

Sedaia [141]

Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the first standard deviation is

$\sigma_1 = \sqrt{v_1}$

=> $\sigma_1 = \sqrt{0.25}$

=> $\sigma_1 = 0.5$

Generally the second standard deviation is

$\sigma_2 = \sqrt{v_2}$

=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

$SE_1 = \frac{\sigma_1}{\sqrt{n} }$

$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

$SE_2 = \frac{\sigma_2}{\sqrt{n} }$

$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

$SE = \sqrt{SE_1^2 + SE_2^2 }$

=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

5 0

3 years ago

F-20f=21 what’s the answer

Virty [35]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{F \ = \ -\frac{21}{19} }}$

$\bold{[ \ Explanation \ ]}$

$\bold{Solve: \ f \ - \ 20f \ = \ 21}$

-----------------------------------

$\bold{Add \ Similar \ Elements:f-20f=-19f}$

$\bold{-19f=21}$

$\bold{Divide \ Both \ Sides \ By \ -19}$

$\bold{\frac{-19f}{-19}=\frac{21}{-19}}$

$\bold{Simplify}$

$\bold{F \ = \ -\frac{21}{19}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

5 0

3 years ago

Solve the system of equations. 10y - 11x = -4 - 2y + 3x = 4

dusya [7]

Answer:

(4,4)

Step-by-step explanation:

The intersection point of 10y-11x=-4 and -2y+3x=4 is (4,4) on a graph.

4 0

2 years ago