A combination is a selection of part from a set of objects. In a combination the order of selecting object does not matters.
So we use combination for selecting 3 from the population of 10
We know combination of selecting 'r' objects from 'n' is nCr
We need to find 10C 3
= 120
120 different samples of size 3 can be taken from a finite population of size 10
Answer:
100 packets
Step-by-step explanation:
Given :
Cost = fixed cost + variable cost
Fixed cost = $500
Variable cost = $10
Sales price = $15
Let :
Number of packets = x
To break even :
fixed cost + variable cost = sales made
500 + 10x = 15x
500 = 15x - 10x
500 = 5x
x = 500 / 5
x = 100
100 packets
Equate the two equations you'll get:
(-6,1) or (2,7)
A=Pe^(rt)
P = 800g
t = 8 years
A = 450g
r = This is what we will try and find to start with
450=800e^(r*8)
After running the math through a calculator, we end with r = -0.07192
Now we just re-input this information into our equation: A=800e^(-0.07192*16)
A=800e^(1.15072)
Now we will re-write the equation using the negative exponent rule:
A = 800 1/e^1.15072
Combine right side:
A = 800/e^1.15072
Then do the math:
A = 253.12709836......
That will give us A = 253 (rounded to the whole number)
I hope this helps! :)