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castortr0y [4]
3 years ago
9

Let f(x) = 16 – x^2, g(x) = 4 – x. Find (fg)(x) and its domain.

Mathematics
1 answer:
pogonyaev3 years ago
5 0

Answer:

x+4; all real numbers except =-4

Step-by-step explanation:

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

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Step-by-step explanation:

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First, let's move the 7 to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:

x^{2} - 4x = 7

From here, since the coefficient of the x term is -4, we know the square will be (x - 2) (since -2 it's half of -4).

To complete this square, we will need to add (-2)^{2} to both sides of the equation:

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x^{2} - 4x + 4 = 7 + 4

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Now we can take the square root of both sides to figure out the solutions to x:

x - 2 = \pm \sqrt{11}

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