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neonofarm [45]
2 years ago
9

The perimeter of a rectangle is 40 inches. If the length of the rectangle is 13 inches, which equation could be used to find the

width,
x?
OA. x + 13 = 40
ОВ.
2(x + 13) = 40
OC. X+2(13) = 40
OD
13(x + 2) = 40
Mathematics
1 answer:
Liula [17]2 years ago
4 0
Answer: OB 2(x+13) = 40
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Step-by-step explanation:

11. shape 1 => A = ½×17×10=85m²

shape 2=> A = 17×9 =153 m²

total area = 238 m²

12. shape 1 => A = 7×3= 21 m²

shape 2=> A = 3×2 = 6 m²

total area = 27 m²

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Put the following numbers in order from least to greatest 2/10 2/9 1/4 .01 .21​
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.01 2/10 .21 2/9 1/4
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PLEASE HELP which number line represents the solution to |x-21|<3
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Answer:solutions, search about Complex Numbers

Step-by-step explanation:−2||=−6

−

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=

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The value inside the absolute value brackets could be positive or negative and give a positive result.

()=3

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 OR  −()=3

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On a number line, that would translate to a number line with two dots on it, one at -3 and one at +3.

7 0
2 years ago
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Cody deposits of $45,$18 and $27 into his checking account. He then wrote checks for $21 and $93.Write an expression to show the
alukav5142 [94]
X= balance
x+45+18+27-21-93 = x - 24 
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2 years ago
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In testing a certain kind of missile, target accuracy is measured by the average distance X at which the missile explodes. The d
3241004551 [841]

Answer:

The answer is c) 761.0

Step-by-step explanation:

Mathematical hope (also known as hope, expected value, population means or simply means) expresses the average value of a random phenomenon and is denoted as E (x). Hope is the sum of the product of the probability of each event by the value of that event. It is then defined as shown in the image, Where x is the value of the event, P the probability of its occurrence, "i" the period in which said event occurs and N the total number of periods or observations.

 The variance of a random variable provides an idea of the dispersion of the random variable with respect to its hope. It is then defined as shown in the image.

Then you first calculate E [x] and E [x^{2}], and then be able to calculate the variance.

E[x]=0*\frac{1}{40} +10*\frac{1}{20} +50*\frac{1}{10} +100*\frac{33}{40}

E[x]=0+\frac{1}{2} +5+\frac{165}{2}

E[X]=88

So <em>E[X]²=88²=7744</em>

On the other hand

E[x^{2} ]=0^{2} *\frac{1}{40} +10^{2} *\frac{1}{20} +50^{2} *\frac{1}{10} +100^{2} *\frac{33}{40}

E[x²]=0+5+250+8250

<em>E[x²]=8505 </em>

Then the variance will be:

Var[x]=8505-7744

<u><em>Var[x]=761 </em></u>

5 0
3 years ago
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