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Yuliya22 [10]
3 years ago
13

Three of these fractions are equivalent: B. 12 C . 21 D. 74 30 A. . 70 Which one is the odd one out?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

Answer:

12/30

Step-by-step explanation:

Here is the complete question

Three of these fractions are equivalent A.30/70 B.12/30 C.9/21 D.6/14 which one is the odd one out

to determine the equivalent fractions, convert the fractions to percentage

\frac{30}{70} × 100 = 42.86%

\frac{12}{30} × 100 = 40%

\frac{9}{21} × 100 = 42.86%

\frac{6}{14} x 100 = 42.86%

Another method is to convert the fraction to its simplest form

30/70

To transform to the simplest form. divide both the numerator and the denominator by 10 = 3/7

12/30

To transform to the simplest form. divide both the numerator and the denominator by 6 = 2/5

9/21

To transform to the simplest form. divide both the numerator and the denominator by 3 = 3/7

6/14

To transform to the simplest form. divide both the numerator and the denominator by 2 = 3/7

Using either methods, 12/30 is the odd one out  

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Answer:

The correct answer is A.

Step-by-step explanation:

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⇒ Charges = 20% of 250000 = $50000

Total charge = Charge × face value

                     = 50000 × 1.86 = $93000

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face value = 1.86 , charges are 18% more for smokers

⇒ Charges = 18% of 250000 = $45000

Total charge = Charge × face value

                     = 45000 × 1.86 = $83700

  • Premium for Company C :

face value = 2.07 , charges are 25% more for smokers

⇒ Charges = 25% of 250000 = $62500

Total charge = Charge × face value

                     = 62500 × 2.07 = $129375

  • Premium for Company D :

face value = 2.25 , charges are 15% more for smokers

⇒ Charges = 15% of 250000 = $37500

Total charge = Charge × face value

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Hence, The option A. is correct that is Aaron is paying the smallest premium possible with company B



8 0
3 years ago
Read 2 more answers
Complete the table of values
Agata [3.3K]
Both problems give you a function in the second column and the x-values. To find out the values of a through f, you need to plug in those x-values into the function and simplify! 

You need to know three exponent rules to simplify these expressions:
1) The negative exponent rule says that when a base has a negative exponent, flip the base onto the other side of the fraction to make it into a positive exponent. For example, 3^{-2} =
\frac{1}{3^{2} }.
2) Raising a fraction to a power is the same as separately raising the numerator and denominator to that power. For example, (\frac{3}{4}) ^{3}  =  \frac{ 3^{3} }{4^{3} }.
3) The zero exponent rule<span> says that any number raised to zero is 1. For example, 3^{0} = 1.
</span>

Back to the Problem:
Problem 1 
The x-values are in the left column. The title of the right column tells you that the function is y =  4^{-x}. The x-values are:
<span>1) x = 0
</span>Plug this into y = 4^{-x} to find letter a:
y = 4^{-x}\\&#10;y = 4^{-0}\\&#10;y = 4^{0}\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = 4^{-x} to find letter b:
y = 4^{-x}\\ &#10;y = 4^{-2}\\ &#10;y =  \frac{1}{4^{2}} \\  &#10;y= \frac{1}{16}
<span>
3) x = 4
</span>Plug this into y = 4^{-x} to find letter c:
y = 4^{-x}\\ &#10;y = 4^{-4}\\ &#10;y =  \frac{1}{4^{4}} \\  &#10;y= \frac{1}{256}
<span>

Problem 2
</span>The x-values are in the left column. The title of the right column tells you that the function is y =  (\frac{2}{3})^x. The x-values are:
<span>1) x = 0
</span>Plug this into y = (\frac{2}{3})^x to find letter d:
y = (\frac{2}{3})^x\\&#10;y = (\frac{2}{3})^0\\&#10;y = 1
<span>
2) x = 2
</span>Plug this into y = (\frac{2}{3})^x to find letter e:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^2\\ y = \frac{2^2}{3^2}\\&#10;y =  \frac{4}{9}
<span>
3) x = 4
</span>Plug this into y = (\frac{2}{3})^x to find letter f:
y = (\frac{2}{3})^x\\ y = (\frac{2}{3})^4\\ y = \frac{2^4}{3^4}\\ y = \frac{16}{81}
<span>
-------

Answers: 
a = 1
b = </span>\frac{1}{16}<span>
c = </span>\frac{1}{256}
d = 1
e = \frac{4}{9}
f = \frac{16}{81}
5 0
3 years ago
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butalik [34]
-6.1=-(6+1/10)

-6 1/10
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3 years ago
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