90,000,000,000
+ 0
+ 100,000,000
+ 70,000,000
+ 5,000,000
+ 0
+ 80,000
+ 7,000
+ 300
+ 0
+ 9
Expanded Factors Form:
9 × 10,000,000,000
+ 0 × 1,000,000,000
+ 1 × 100,000,000
+ 7 × 10,000,000
+ 5 × 1,000,000
+ 0 × 100,000
+ 8 × 10,000
+ 7 × 1,000
+ 3 × 100
+ 0 × 10
+ 9 × 1
Expanded Exponential Form:
9 × 1010
+ 0 × 109
+ 1 × 108
+ 7 × 107
+ 5 × 106
+ 0 × 105
+ 8 × 104
+ 7 × 103
+ 3 × 102
+ 0 × 101
+ 9 × 100
Word Form:
ninety billion, one hundred seventy-five million, eighty-seven thousand, three hundred nine
Answer: True
Step-by-step explanation:
The area of a trapezoid is ((b1+b2)/2)*h.
Because this trapezoid is an isosceles trapezoid, we can find the base of the right triangles: 4. Then, using Pythagorean theorem we can get the height of the trapezoid, the square root of 33, or about 5.75. Then plugging the values into the formula, we get 86.25, which is close to 86.2.
Hope it helps <3
The next 3 terms would be -162, 468, 1457
4/10 the second one is 6/10 why because the number line goes by tens so ten is always under the fraction of the number line
Number of possible outcome for tossing N coins = ![2^N](https://tex.z-dn.net/?f=2%5EN)
Solution:
Possible outcomes when tossing one coin = {H, T}
Number of possible outcomes when tossing one coin = 2 ![=2^1](https://tex.z-dn.net/?f=%3D2%5E1)
Possible outcomes when tossing two coins = {HH, HT, TH, TT}
Number of possible outcomes when tossing two coins = 4 ![=2^2](https://tex.z-dn.net/?f=%3D2%5E2)
Possible outcomes when tossing three coins
= {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Number of possible outcomes when tossing three coins = 8 ![=2^3](https://tex.z-dn.net/?f=%3D2%5E3)
Therefore, the sequence obtained is
.
If continue this sequence, we can obtain number of possible outcome for tossing N coins is
.