Answer:
1.) Zero ( 0 )
2.) 55.47 feet , 8.6 feet
3.) 17.2 feet
Step-by-step explanation:
The height, in feet, of the ball is given by the equation h(x)=−.25x2+4.3x, where x is the number of feet away from the golf club (along the ground) the ball is.
1.) Since the equation has no intercept,
The ball will start zero feet above the ground.
2.) The distance of the ball at the maximum height will be achieved by using the formula
X = -b/2a
Where b = 4.3, a = -0.25
Substitutes both into the formula
X = -4.3 / 2( - 0.25 )
X = - 4.3 / - 0.5
X = 8.6 feet
Substitute X into the function to get the maximum height
h(x) = −.25(8.6)^2 + 4.3(8.6)
h(x) = 18.49 + 36.98
h(x) = 55.47 feet
3) As the ball returns to the ground, the height will be equal to zero, therefore,
0 = -0.25x^2 + 4.3x
0.25x^2 = 4.3x
X = 4.3/0.25
X = 17.2 feet
The ball returns to the ground at about 17.2 feet away
Answer:
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Answer:
the answer is 15
Step-by-step explanation:
Given data:
Volume V = 45 π and radius
r = 3 units The formula for the volume of the cylinder is V = B · H
Base of the cylinder is:
B = r² π = 3² π = 9 πFrom the formula V = B · H we get H:H = V / B = 45 π / 9 π = 5 units
H = 5 units
Answer: 67.500 ft²
Explanation:
1) Name the dimensions using variables:
y: length of the rectangular field
x: widht of the rectangular field
2) Model the amount of fence used by the two equal pastures:
two sides and one internal fence: 2x + x = 3x
two lengths: 2y
⇒ 3x + 2y = 1800 ← linear feet of fence
y = 1800 / 2 - 3x/2 ← solving for y
y = 900 - 3x/2
3) Area of each pasture
A = x(y/2) ← half ot xy
A = x (900 - 3x/2) ← replacing y with 900 - 3x/2
A = 900x - 3x² / 2 ← using distributive property
4) Maximum area ⇒ A' = 0
A' = 900 - 3x ← derivative of the polynomial 900x - 3x² / 2
900 - 3x = 0
⇒ 3x = 900
⇒ x = 900/3
⇒ x = 300
4) Determine y
y = 900 - 3x/ 2 = 900 - 3(300)/2 = 900 - 450 = 450
5) Area of each pasture
A = xy/2 = 300 × 450 /2 = 67500 ← final answer
Answer:
Step-by-step explanation:
The answer is 20q^17w^9