1) we have to calculate the first derivative:
h´(t)=-32t+32
2)the first derivative equate to "0"
-32t+32=0
3) obtein value of "t"
-32t+32=0
t=-32/32=1
4) we have to calculate the second derivative
h´´(T)=-32<0 ⇒ exist a maximum in t=1
5) now calculate the maximum height.
h(1)=20-16(1)²+32(1)=36 m
Answer: the maximum heigth was 36 m
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explain your question more please.
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Answer:
140
Step-by-step explanation:
I MIGHT JOIN JUST NOT NOW
Step-by-step explanation:
gotta do hw >:(
also how old are you cuz im 13 and don't wanna talk to an old man