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2 years ago

The figure below is divided into 100 small squares of equal size.

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

4 0

Answer:

0.7, 70/100 or 7/10

Step-by-step explanation:

70 squares are shaded.

So 70/100 of all squares are shaded

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6/y=9/24 whats the proportion? a= 16 b= 19 c= 20 d=21

Sveta_85 [38]

The answer is: a = 16

Steps:

First exclude any restricted values of y.

6/y = 9/24 , y is not equal 0

Simplify the right side of the equation using 3.

6y = 3/8

Cross multiply.

6 x 8 = 3
3 x y = 3y
So, 6 x 8 = 3y
Or, 48 = 3y

Switch the sides of the equation.

3y = 48

Divide both sides by 3.

3y/3 = y
48/3 = 16

Now you have your answer, y = 16

7 0

3 years ago

You get internet service for a flat rate of $ 16.95 per month regardless of the number of minutes that you spend online. The tab

shusha [124]

Whats the question???????????????????????????

8 0

3 years ago

The monthly worldwide average number of airplane crashes of commercial airlines is 2.2. What is the probability that there will

Makovka662 [10]

Answer:

(a) more than 2 such accidents in the next month $\approx 0.3773$

(b) more than 4 such accidents in the next 2 months $\approx 0.44882$

(c) more than 5 such accidents in the next 3 more than 5 such accidents in the next 3 months $\approx 0.64533$

Step-by-step explanation:

Let N be the Random variable that marks the number of crashes in certain month.

Now let us use Poisson distribution since we are given with average number of crashes that is N \sim Pois(2.2)

(A) more than 2 such accidents in the next month

Probability(more than 2 such accidents in the next month)=P(N>2)

P(N>2)=1-P(N=0)-P(N=1)-P(N=2)

=> $1-e^-{2.2}-2.2e^{-2.2}-\frac{2.2^2}{2!}e^{2.2}$

=> $\approx 0.3773$

B) more than 4 such accidents in the next 2 months

since the average number of crashes in 1 month is 2.2, the average number of crashes in two months is 4.4. hence, if we say that $N_1$ is the number of crashes in 2 months, we have that $N\sim$ Pois(4.4)

Thus,

Probability(more than 4 such accidents in the next 2 months)=P( $N_1>4$ )

= $1-P(N_1=0)-P(N_1=1)-P(N_1=2)=P(N_1=3)-P(N_1=4)$

$1-\sum_{k=1}^{4} \frac{4.4^{k}}{k !} e^{-4.4}$

=> $\approx 0.44882$

C) more than 5 such accidents in the next 3 more than 5 such accidents in the next 3 months

If we say that $N_2$ marks the number of crashes in the next 3 months , using the same argument as in (a) we have that a $N\sim$ Pois(6.6)

Hence

P( $N_2>5$ )= $1-\sum_{k=0}^{5} \frac{6.6^{k}}{k !} e^{-6.6}$

=> $\approx 0.64533$

6 0

3 years ago

Simplify (8 - 4)|+|-3

Anika [276]

Answer:

tell me if im right

Step-by-step explanation:

5 0

3 years ago

Using Order of Operations, you always do Multiplication before Division

katrin2010 [14]

Answer: No you dont. But you also do not have to divide either. order of operations means following what comes first, so what ever comes first is what you do. Follow PEMDAS

Step-by-step explanation:

6 0

3 years ago