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love history [14]
3 years ago
7

Please help ill mark brainliest ✅✅✅✅

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

i think y=3/4x-4.2

Step-by-step explanation:

You might be interested in
Pls help me with this question
k0ka [10]

Answer:

height = 12 feet

Step-by-step explanation:

r (radius of circle) = 7 ft

pi = 3.14 (in this context)

v = 1/3 * πr^{2} (or pi * radius squared) * h

r squared = 49 ft

v = 1/3 3.14 * 49 * h

v = 1/3 153.86 * h

3v = 153.86 * h

v = 196π

v = 615.44

3v = 1,846.32

1,846.32 = 153.86 * h

h = 12 ft.

3 0
3 years ago
Rose has made this scale drawing of her house. How wide is her house?
Bumek [7]

Answer:

D) 70 ft

Step-by-step explanation:

1 inch = 20 feet

3 1/2 inches= 20 feet*3 1/2 inches

= 70 ft

6 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
3/11 - 2.12<br> ANSWER PLEASE
harina [27]

Answer:

-1.84727272727

Step-by-step explanation:

calculator

3 0
3 years ago
(17-7)•6+2+56-8<br> Pemdas
givi [52]
I don’t even know the answer to be honest
4 0
4 years ago
Read 2 more answers
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