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3 years ago

PLEASE HELP ME !!!!!!!!!!!!!!!!!LET ME KNOW IF ITS RIGHT

Mathematics

1 answer:

Savatey [412]3 years ago

4 0

Okay. So the song lasts 221 seconds. 45 seconds have already beem done and 22 seconds is done in an hour. The equation would be set up like this:

45 + 22h = 221

Just by looking at the answer choices, A is already eliminated because it doesn't incorportate the 45 seconds. B does include the 45 seconds, but it subtracts, and in this case, we add time, not subtract. D is eliminated, because the h variable does not go with 45. The only equation that works is C and when you solve it, you get 8 hours. The answer is C.

Note: you solve the equation above by subtract 45 from both sides to get 176 = 22x, and dividing both sides by 22 to get x = 8.

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Jane is planting a mixture of flowers. For every ounce of Marigold seeds she uses 2/5 of an ounce of lupine seeds how many ounce

dusya [7]

Answer:

$\frac{5}{2}$ ounces of marigold seeds.

Step-by-step explanation:

We have been given that Jane uses 2/5 of an ounce of lupine seeds for every ounce of Marigold seeds. We are asked to find the ounces of Marigold seeds, which Jane will use, if she used one ounce of lupine seeds.

We will use proportions to solve our given problem.

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1}{\frac{2}{5}}$

Let us simplify our proportion as shown below:

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{1\cdot 5}{2}$

$\frac{\text{Marigold seeds}}{\text{Lupine seeds}}=\frac{5}{2}$

Since Jane used 1 pounce of lupine seeds, so we will substitute this value in our proportion as:

$\frac{\text{Marigold seeds}}{1}=\frac{5}{2}$

$\text{Marigold seeds}}=\frac{5}{2}$

Therefore, Jane will use $\frac{5}{2}$ ounces of marigold seeds, if she used one ounce of lupine seeds.

6 0

3 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find h'(x)
h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

 h'(x) = 1.44 ------------ > not exist

8 0

3 years ago

10=ax+bx solve for x With steps please

laila [671]

Answer:

$\displaystyle 10 = ax + bx \rightarrow x = \frac{10}{a + b}$

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Factoring

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle 10 = ax + bx$

Step 2: Solve for x

Factor: $\displaystyle 10 = ax + bx \rightarrow 10 = x(a + b)$
[Division Property of Equality] Divide a + b on both sides: $\displaystyle 10 = ax + bx \rightarrow x = \frac{10}{a + b}$

7 0

3 years ago

Help on this question please!!!

OLga [1]

Answer:

Hello! Here is your answer

Step-by-step explanation:

112=4(28)

a=4b

You can only have one variable so:

Combine b to a:

a-b=84

4b-b=84

Divide both sides by 3:

3b/3=84/3

b=28

But that is not it:

Sum of both cards:

a+b

a=112

b=28

112+28=140

= 140

I hope I was of help. If not please let me know! Thank you! Good luck!

4 0

3 years ago

Increase 90 in the ratio 5 is to 3

cupoosta [38]

9514 1404 393

Answer:

150

Step-by-step explanation:

The increase is by the factor 5/3, so the increased number is ...

90×(5/3) = 150

90 increased in the ratio 5 : 3 is 150.

5 0

3 years ago