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goldenfox [79]
4 years ago
11

PLEASE HELP ME !!!!!!!!!!!!!!!!!LET ME KNOW IF ITS RIGHT

Mathematics
1 answer:
Savatey [412]4 years ago
4 0
Okay. So the song lasts 221 seconds. 45 seconds have already beem done and 22 seconds is done in an hour. The equation would be set up like this:

45 + 22h = 221

Just by looking at the answer choices, A is already eliminated because it doesn't incorportate the 45 seconds. B does include the 45 seconds, but it subtracts, and in this case, we add time, not subtract. D is eliminated, because the h variable does not go with 45. The only equation that works is C and when you solve it, you get 8 hours. The answer is C.

Note: you solve the equation above by subtract 45 from both sides to get 176 = 22x, and dividing both sides by 22 to get x = 8.
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Answer:

\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

Step-by-step explanation:

\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a

=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

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