Please help me with this geometry question

Graph the function with the given domain then identify the range of the function

alexira [117]

When the domain is ≥ to 0, that basically means that x must be ≥ 0.
Imagine what that looks like.
It would just be the right side of the coordinate plane, right? Because the left side would have negative x values.

We're basically just going to be graphing the line $y=3x-2$ , except only the part on the right side of the coordinate plane because of course x ≥ 0.

When you have an equation in the form of $y=mx+b$ , $b$ is going to be the y-intercept (the point where the line intersects the y-axis) and $m$ is going to be the slope.

Since the y-intercept is -2, draw a point at (0, -2).

Then, use the slope to find another point on the line.
The slope is 3, which as a fraction would be $\frac{3}1$ .
Slope = rise over run, so basically every change of 1 in x = a change of 3 in y.
Draw a point 3 up and 1 over from (0, -2).<em> (at (1, 1))

</em>Then draw a line through the two points we have graphed. Don't draw past the y-axis on the left side, because of course x ≥ 0.
<em>
And there you go!
</em>
The range of the function is basically the possible values y can have.
Well, since it's not going any lower than the y-intercept (0, -2), the range is ≥ -2.<em>

</em>

6 0

3 years ago

True or false two lines that lie in a parallel planes are parallel

faltersainse [42]

True ................

4 0

3 years ago

Choose the correct solution and graph for the inequality "-x/3<=6"

lina2011 [118]

Answer:

Step-by-step explanation:

To solve this inequality, we have to find x (or make x the subject of the inequality:

since ⁻ˣ/₃ ≤ 6 [multiply both sides by 3]

- x ≤ 18 [multiply both sides by -1; this flips the inequality sign]

<h3> x ≥ - 18 [this is the solution]</h3><h3 />

To graph the inequality, draw the line x = - 18 with a solid line, and then shade the region that is x > -18.

We use a solid line because the point x = -18 is included. However, hypothetically, if the inequality was x > -18 only, a broken line would be used to show that the line x = -18 is not included.

7 0

3 years ago

Please help its7to10 I be waiting like two hours

Bingel [31]

Answer:

Please check the explanation!

Step-by-step explanation:

Important factors to remember regarding the like terms:

'Like terms' are terms whose variables such as 2x and 6x are the same.

Also if the variables contain the exponents such as 4 in x⁴, they must be the same too.

Since the coefficient doesn't affect likeness, therefore we can say that all constant terms would be treated as the like terms.

Question 7

Given the terms

2b b⁶ b x⁴ 3b⁶ 2x²

From the list of terms, there are two groups of like terms which are:

2b b (Like terms containing the variable b)

b⁶ 3b⁶ (Like terms containing the variable b with the same exponents)

The remaining two x⁴ and 2x² terms are different from each other and the rest of the terms

Question 8

Given the terms

6 2n 3n² 3m² n/4 7

From the list of terms, there is one group of like terms which are:

6 7 (Constants Like terms)

2n n/4 (The terms with the same variable n)

All the remaining terms such as 3n², 3m² are all different from each other and the rest of the terms.

Question 9

Given the terms

10k² m 3³ p/6 2m

From the list of terms, there are there is one group of like terms which are:

m 2m (The terms withe same variable m)

All the remaining terms such as 10k², 3³, p/6 are all different from each other and the rest of the terms.

Question 10

Given the terms

6³ y³ 3y² 6² y 5y³

From the list of terms, there are two groups of like terms which are:

y³ 5y³ (The terms withe same variable m and exponent)

6³ 6² (Constant like terms. Plz don't confuse the power as all are the same constant terms)

All the remaining terms such as y and 3y² are all different from each other and the rest of the terms.

6 0

3 years ago

Which of the following correctly describes confidence level?

soldier1979 [14.2K]

Answer:

d

Step-by-step explanation:

7x7x7x7x7x7x7x7x7x7x7x7x7x7x7 is 12345667

4 0

4 years ago