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3 years ago

139 subtracted by what would give me the number 23?

Mathematics

1 answer:

a_sh-v [17]3 years ago

5 0

139 subtracted by 116 gives you 23

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an office building is 5 times as tall as a house. if the difference in their height is 100, how tall is the building

nalin [4]

Answer: 20

20 since you have to divide 100 by 5 which equals 20 since you have to use the inverse operation of multiplication which is division.

Hope this helps!

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3 years ago

Maggie claims that there are transformations that preserve the length of the rectangle's sides. Which of the following transform

Nataly_w [17]

Answer:

B, D, and E

Step-by-step explanation:

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3 years ago

How do I graph this equation on a graph

Sergeu [11.5K]

Answer:

The equation is in standard form. You will have to convert it to slope intercept form, which is -0.125x + 3.75 = y

Step-by-step explanation:

s = x and a = y, therefore 0.5x + 4y = 15

0.5x + 4y = 15

0.5x + 4y = 15 first subtract 0.5x

4y = -0.5x + 15 then divide all by 4

y = -0.125x + 3.75 slope intercept form

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3 years ago

I have a 6 grader thst needs help with percentages; what assistance do you have here.

mr Goodwill [35]

Answer:

welp we can help them solve the question and we could also help you by teaching them with you if you need assistance

Step-by-step explanation:

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3 years ago

Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.

Georgia [21]

Answer:

Step-by-step explanation:

First, let's find x.

We know that one of the angles is 30. The side opposite to than angle is 11, and x is the adjacent side to it. Therefore, we can use the trig function tangent.

Recall that:

$\tan(x)=opp/adj\\$

Plug in 30 for the angle, 11 for the opposite, and x for the adjacent. Solve for x by cross-multiplying:

$\tan(30)=11/x\\x\tan(30)=11\\x=11/\tan(30)$

From the unit circle, recall that tan(30) is equal to one over the square root of 3. Thus:

$x=11/(1/\sqrt3)\\x=11\cdot\sqrt3\\x=11\sqrt3$

Now, we can use the Pythagorean Theorem to find y. y is the hypotenuse. Thus:

$c^2=a^2+b^2\\c^2=(11\sqrt3)^2+11^2\\c^2=121(3)+121\\c^2=4(121)\\c^2\sqrt{4(121}=2(11)=22$

6 0

3 years ago